Maximum Volume of Folded Box: Proving and Solving Using Differentiation

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SUMMARY

The discussion focuses on calculating the maximum volume of an open box formed by cutting squares from the corners of a rectangular zinc sheet measuring 30 cm by 16 cm. The volume of the box is expressed as V = 4(x^3 - 23x^2 + 120x) cm³. Participants discuss the differentiation process necessary to find the maximum volume, emphasizing the importance of understanding the relationship between the box's dimensions and its volume. The conversation also highlights the relevance of differentiation, referred to as "Pembezaan" in Malay, in solving optimization problems.

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  • Understanding of basic geometry and volume calculations
  • Knowledge of differentiation and its applications
  • Familiarity with polynomial functions and their properties
  • Ability to interpret mathematical expressions and equations
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  • Study the principles of optimization in calculus
  • Learn how to apply the first and second derivative tests for finding maxima and minima
  • Explore the concept of volume in three-dimensional geometry
  • Practice solving real-world problems involving differentiation and optimization
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Mmx
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Sorry my maths question is in Malay ill try to translate as gd as i can. I realyl have no idead how to do it.

A zink which have a square size of 30 cm x 16 cm.
At the end of the 4 edge of the sqaure zink is cut out equally same sides x cm.

After cutting the zink is fold into a a open box.

a) Prove that the volume, V of this box is equal to V=4(x^3 - 23x^2 + 120x)cm^3

b) After that, find the maksimum volume, V

If you can understand then nvm cause my maths are in malay and not english. In malay this topic are call Pembezaan I am not sure in english that is call differences. I can understand better with the look of working. Sorry:cry:
 
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Mmx said:
Sorry my maths question is in Malay ill try to translate as gd as i can. I realyl have no idead how to do it.

A zink which have a square size of 30 cm x 16 cm.
At the end of the 4 edge of the sqaure zink is cut out equally same sides x cm.

After cutting the zink is fold into a a open box.

a) Prove that the volume, V of this box is equal to V=4(x^3 - 23x^2 + 120x)cm^3

b) After that, find the maksimum volume, V

If you can understand then nvm cause my maths are in malay and not english. In malay this topic are call Pembezaan I am not sure in english that is call differences. I can understand better with the look of working. Sorry:cry:
Okay, I think I understand what you mean...
Do you know the formula for computing the volume of a box: [tex]\mbox{V = length x height x depth} = \mbox{A_{base}} \mbox{ x height}[/tex]?
So after you fold that zink into an open box, what's the length, the depth, and the height of that box?
So, your zink will look like this:
__|¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯|__
|...........|
|...........|
|...........|
|...........|
¯¯|_______________|¯¯
Hint, the base is the rectangle in red. Can you find its area?
Can you find the height of the box?
From there, can you find its volume?
--------------
For number 2, do you know how to differentiate?
For example f(x) := x3 + x
=> f'(x) = 3x2 + 1.
Can you do this?
If yes, then do you know how one can find an maximum value and minimum value of a function by differentiation?
 
Last edited:
Thx. Yes i know how to differentiate that's y my malay call Pembezaan. Thx for the hint. I Can do it now.
 

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