- #1
Niles
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Hi
I have a question regarding the Maxwell-Bloch equations, which I read about in a dissertation. I've looked through many papers online, but no one offers an answer. It is a very specific question, which is based on the first 2-3 lines on page 13 of this thesis: http://mediatum2.ub.tum.de/download/652711/652711.pdf
It is regarding the statement above equation (2.23a): The author states that
[tex]
\left\langle {o^\dagger} \right\rangle = \left\langle {o} \right\rangle^*
[/tex]
which I agree 100% with. Now the author uses this relation to go from an equation for [itex]\left\langle {a} \right\rangle [/itex] to an equation for [itex]\left\langle {a^\dagger a} \right\rangle[/itex]. However this is what I don't understand, because
[tex]
\left\langle a \right\rangle \left\langle a \right\rangle ^* = \left\langle a \right\rangle \left\langle {a^\dagger } \right\rangle = \left\langle {a^\dagger } \right\rangle \left\langle a \right\rangle \ne \left\langle {a^\dagger a} \right\rangle
[/tex]
Does anyone know what the assumption is for making this factorization? I would be very happy to receive some feedback.Niles.
I have a question regarding the Maxwell-Bloch equations, which I read about in a dissertation. I've looked through many papers online, but no one offers an answer. It is a very specific question, which is based on the first 2-3 lines on page 13 of this thesis: http://mediatum2.ub.tum.de/download/652711/652711.pdf
It is regarding the statement above equation (2.23a): The author states that
[tex]
\left\langle {o^\dagger} \right\rangle = \left\langle {o} \right\rangle^*
[/tex]
which I agree 100% with. Now the author uses this relation to go from an equation for [itex]\left\langle {a} \right\rangle [/itex] to an equation for [itex]\left\langle {a^\dagger a} \right\rangle[/itex]. However this is what I don't understand, because
[tex]
\left\langle a \right\rangle \left\langle a \right\rangle ^* = \left\langle a \right\rangle \left\langle {a^\dagger } \right\rangle = \left\langle {a^\dagger } \right\rangle \left\langle a \right\rangle \ne \left\langle {a^\dagger a} \right\rangle
[/tex]
Does anyone know what the assumption is for making this factorization? I would be very happy to receive some feedback.Niles.