Mean and Autocorrelation of a Deterministic Function

Click For Summary

Discussion Overview

The discussion revolves around the mean and autocorrelation of deterministic functions, particularly in the context of random processes. Participants explore definitions and implications of these concepts, comparing them to established definitions in stochastic processes.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant defines the mean of a process \(X(t)\) as \(E[X(t)]\) and contrasts it with the time average, suggesting a specific example involving sine functions.
  • Another participant provides an integral definition of expectation for a deterministic signal over a specified interval, emphasizing the need to consider how values outside the defined set are treated in correlation calculations.
  • There is a request for simple Yes/No answers to the initial questions posed, indicating a desire for clarity or confirmation of understanding.
  • A participant highlights the distinction between local averages at specific points and a global mean, suggesting that the autocorrelation function's definition for deterministic functions has already been addressed.

Areas of Agreement / Disagreement

Participants express differing views on the definitions and implications of mean and autocorrelation for deterministic functions versus stochastic processes. There is no consensus reached on the interpretations or the implications of these definitions.

Contextual Notes

Participants discuss the treatment of functional values outside the defined interval and the implications for correlation, indicating potential limitations in the definitions provided.

OhMyMarkov
Messages
81
Reaction score
0
Hello everyone!

I have a couple of questions related to random processes:

(1) Isn't the mean of a process $X(t)$ defined as $E[X(t)]$ which, for example, if $X(t)$ belongs of a countable and finite set, would defined as the some of the elements of this set weighted by their corresponding probability and divided by the cardinality of the set. For example:

$X(t) \in \{\sin(2\pi t), \sin(2\pi t + 2\pi/3), 8\sin(2\pi t -2\pi /3)\}$ each with probability 1/3, then the mean of $X(t)$ would be $(7/3) \cdot \sin(2*\pi t)$

This is how the mean is defined, and it is different than the "time" average of $X(t)$ whatever that is supposed to mean for a random process (I know what it means for a deterministic function).

(2) I've know before that the autocorrelation function of a stochastic process $X(t)$ that is stationary in the wide sense is $R_X (k) = E[X(t)X(t+k)]$. But what if the function is deterministic, how would the autocorrelation be defined?

I'm considering this example:

$X(t) = \sin(2\pi t)$ for $0<t<\pi /2$ with probability 1. Then, $R_X (k) = \sin(2\pi t)\cdot \sin(2\pi t + 2\pi k)$ which is not maximum at $k=0$ for an arbitrary time instant. Am I missing something here :confused:?Any help/clarification is appreciated.
 
Physics news on Phys.org
The expectation of a function is the integral of the function over a space with respect to a measure. In the case of a deterministic signal on \(0<t<\pi/2\):

\[E( f)=\int_{0}^{\pi/2} f(t) \frac{2}{\pi}dt\]

Which is of course the expectation of the RV \( f( T)\) where \( T\sim U(0,\pi/2)\).

With a correlation you need to be careful about how functional values for points outside the set on which the function is defined are handled (usually they are taken as zero )

CB
 
Hello CaptainBlack,

Would you mind giving me a Yes/No answer to questions (1) and (2)? I appreciate it.
 
OhMyMarkov said:
Hello CaptainBlack,

Would you mind giving me a Yes/No answer to questions (1) and (2)? I appreciate it.

1. You need to distinguish between the average at a point and the global mean that is between: \( E( X(t)) \) and \( E(X) \), where the first is still a function of \( t\) and the second is not.

2. Since the auto-correlation is an expectation I have already indicated how it is defined for a deterministic function.

CB
 

Similar threads

Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K