Mean & Std Dev for Norm Dist. Exam Marks - 450 Stud.

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SUMMARY

The discussion focuses on calculating the mean and standard deviation of exam marks, assuming a normal distribution among 450 candidates. Given that 25 students scored 60% or more (first class) and 90 students scored less than 30% (failed), the mean and standard deviation can be derived using statistical methods. The normal distribution properties and the percentages of students in each category are crucial for these calculations.

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  • Understanding of normal distribution in statistics
  • Knowledge of mean and standard deviation calculations
  • Familiarity with statistical notation and terminology
  • Basic proficiency in statistical software or tools for calculations
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  • Learn how to calculate mean and standard deviation for a normal distribution
  • Explore the properties of normal distribution and its applications
  • Study the use of statistical software like R or Python for data analysis
  • Investigate the implications of different distributions on exam performance analysis
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wajeehayas
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Assuming that the number of marks scored by a candidate is normally distributed, find the mean and the standard deviation, if the number of first class students(60% or more marks) is 25, the number of failed students(less than 30%marks) is 90 and the total number of candidates appearing for the examination is 450.
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Hello wajeehayas and welcome to MHB! :D

We ask that our users show their progress (work thus far or thoughts on how to begin) when posting questions. This way our helpers can see where you are stuck or may be going astray and will be able to post the best help possible without potentially making a suggestion which you have already tried, which would waste your time and that of the helper.

Can you post what you have done so far?
 

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