- #26

MathematicalPhysicist

Gold Member

- 4,295

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OK, I see my error, thanks for pointing it out to me all of you.

Sorry to be stubborn, just when you get older you get to be stubborner.

But I agree if ##c \ne 0## then we get ##\pm \infty = 0## which is obviously a contradiction, thus ##c=0##.

So we get: ##\lim c(k+1)= \lim 0(k+1)=0##.

So foolish of me... :-(

Is there an option to delete this thread? I don't see an option somewhere.