Measurement of Lx: Result of Measurement?

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SUMMARY

The measurement of the angular momentum operator \(L_x\) for a wave function \(\psi = g(r)|1,0\rangle\) can be calculated using the operator \(L_x = \frac{1}{2}(L_+ + L_-)\). The resulting action on the wave function yields \(L_x |\psi\rangle = \frac{1}{2} \sqrt{2} g(r) |1,1\rangle\). To determine the outcome of an individual measurement, one must utilize the differential form of the operator \(L_x\) and integrate the product of the wave function and its complex conjugate over the entire space. This approach will provide the expected value, which may not necessarily be zero.

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Physgeek64
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Homework Statement


If we have a wave function ##\psi =zf(r)## and we take a measurement of ##L_x## what is the result of the measurement?

Homework Equations

The Attempt at a Solution


So i know we can write ##L_x=\frac{1}{2}(L_+ + L_- )## and that ##|\psi > = g(r) |1,0> ## so ##L_x |\psi >= \frac{1}{2} \sqrt{2} g(r) |1,1>##. But i don't know what the measurement would be because this has to be an eigenvalue equation to read off the result of a measurement (I think?).

Many thanks!
 
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Physgeek64 said:

The Attempt at a Solution


So i know we can write Lx=12(L++L−)Lx=12(L++L−)L_x=\frac{1}{2}(L_+ + L_- ) and that |ψ>=g(r)|1,0>|ψ>=g(r)|1,0>|\psi > = g(r) |1,0> so Lx|ψ>=12√2g(r)|1,1>Lx|ψ>=122g(r)|1,1>L_x |\psi >= \frac{1}{2} \sqrt{2} g(r) |1,1>. But i don't know what the measurement would be because this has to be an eigenvalue equation to read off the result of a measurement (I think?).

Many thanks!

you have a given wave function which is a function of r and theta only
if you wish to find expected value of L(x) then one must use differential form of the operator L(x)
 
drvrm said:
you have a given wave function which is a function of r and theta only
if you wish to find expected value of L(x) then one must use differential form of the operator L(x)
But how do i find the result of a measurement. I can show that the expected value is zero, but i don't know what the outcome of an individual measurement would be.
 
Physgeek64 said:
But how do i find the result of a measurement. I can show that the expected value is zero, but i don't know what the outcome of an individual measurement would be.

In QM the measurement is defined with the help of wave function
say you have a position wavefunction then you can measure x-operator

as {Psi * (x )Psi }integrated over the whole space.
similarly L(x) is a operator which is represented in (r,theta, phi) space .

put the complex conjugate of the wave function on the left and psi on the right and L(x) in between and integrate over whole space .
the result will give you measurement and it may not be zero.
 

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