Mechanical ad Electrical vibration EASY question ?

Click For Summary
SUMMARY

The discussion centers on the derivation of the general solution for the second-order linear differential equation mu'' + ku = 0, as presented in the Boyce and DiPrima textbook. The solution is expressed as u = Acos(ωt) + Bsin(ωt), where ω² = k/m. The connection between the trigonometric functions and the differential equation is clarified by noting that the second derivatives of cos(ωt) and sin(ωt) yield the original equation, specifically -ω²cos(ωt) and -ω²sin(ωt), respectively. A supplementary resource is provided for further understanding of the topic.

PREREQUISITES
  • Understanding of second-order linear differential equations
  • Familiarity with trigonometric functions, specifically sine and cosine
  • Basic knowledge of mechanical vibrations and their mathematical modeling
  • Experience with differential calculus and its applications
NEXT STEPS
  • Study the derivation of solutions for second-order linear differential equations
  • Learn about the applications of trigonometric functions in mechanical systems
  • Explore the relationship between mechanical vibrations and differential equations
  • Review the provided resource on second-order linear equations for deeper insights
USEFUL FOR

Students and professionals in engineering, particularly those focusing on mechanical and electrical systems, as well as anyone studying differential equations and their applications in vibration analysis.

dwilmer
Messages
11
Reaction score
0
Mechanical ad Electrical vibration EASY question please help?

In Boyce and Diprima textbook it says that:

mu'' + ku = 0 .

Then it says the general solution of this is:

u = Acos (w^2)t + B sin (w^2)t , where w^2 = k/m


It provides no explanation how it arrives at this. Where does the cos and sin come from?

PS: it is supposed to be the greek letter w, whatever that is called and it also has a sub-0 on it, but i didnt include it because it looks confusing without the right fonts.

please help, thanks
 
Physics news on Phys.org
Welcome to PF!

Hi dwilmer! Welcome to PF! :smile:

(have a little omega: ω and try using the X2 tag just above the Reply box :wink:)
dwilmer said:
mu'' + ku = 0 .

Then it says the general solution of this is:

u = Acos (w^2)t + B sin (w^2)t , where w^2 = k/m


It provides no explanation how it arrives at this. Where does the cos and sin come from?

Because [cos(ωt)]'' is obviously -ω2cos(ωt), and [sin(ωt)]'' is obviously -ω2sin(ωt) :smile:
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
6K