Mechanics 1 Help: Solve Questions on Bead Equilibrium

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Homework Help Overview

The discussion revolves around a Mechanics 1 problem involving a bead in equilibrium on a string, with a focus on resolving forces to find tension and weight. The problem includes a horizontal force acting on the bead and requires understanding of trigonometric relationships in a right triangle.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup of the problem, particularly the diagram and the components of tension. Questions arise about the correct use of sine and cosine in resolving forces, especially in relation to the angle x.

Discussion Status

Some participants have provided guidance on how to approach the problem, particularly in resolving forces. There is acknowledgment of understanding gained regarding part (a), while part (b) remains a point of inquiry with emphasis on vertical force resolution.

Contextual Notes

Participants note the importance of correctly identifying the forces acting on the bead and ensuring the equilibrium condition is satisfied. There is mention of a potential misunderstanding regarding the application of trigonometric functions in the context of the problem.

CathyLou
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[SOLVED] Mechanics 1 help

Hi.

Could someone please help me with the following M1 level questions?

A smooth bead B is threaded on a light inextensible string. The ends of the string are attached to two fixed points A and C on the same horizontal level. The bead is held in equilibrium by a horizontal force of magnitude 6 N acting parallel to AC. The bead B is vertically below C and angle BAC = x. tan x = 3/4.

(a) Find the tension in the string.


I drew a diagram and wrote down:

Resolving horizontally:

6 - Tsinx = 0

sin x = 3/5 so T = 10 N.

However, the answer should be 7.5 N. This means that I should be using cos x but I do not understand why this is the case.

(b) Find the weight of the bead.

Would I need to resolve vertically here? If yes, could someone please help me to form the resulting equation.

I would really appreciate any help as I am really stuck at the moment.

Thank you.

Cathy
 
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For part (a), I'm assuming that you've either drawn or are given a diagram. If your diagram is set up correctly, the tension should be acting along the hypotenuse (BA) of a right angled triangle from B to A and the angle x should be the angle between the hypotenuse and the side AC. Now, you need to find the horizontal component of the tension, and this component acts parallel to the line CA which is adjacent to the angle x.

Does that make sense?
 
Hootenanny said:
For part (a), I'm assuming that you've either drawn or are given a diagram. If your diagram is set up correctly, the tension should be acting along the hypotenuse (BA) of a right angled triangle from B to A and the angle x should be the angle between the hypotenuse and the side AC. Now, you need to find the horizontal component of the tension, and this component acts parallel to the line CA which is adjacent to the angle x.

Does that make sense?

Hi.

Thank you for your help! I understand how to do part (a) now.

Could you please help with (b) also?

Cathy
 
CathyLou said:
Hi.

Thank you for your help! I understand how to do part (a) now.

Could you please help with (b) also?

Cathy
For (b), yes you have to resolve the forces vertically and you know that since the bead is in equilibrium the sum of these forces must be zero. So, what forces are acting on the bead? (Be careful with the tension)
 
Hootenanny said:
For (b), yes you have to resolve the forces vertically and you know that since the bead is in equilibrium the sum of these forces must be zero. So, what forces are acting on the bead? (Be careful with the tension)

I have worked out the correct answer now. Thank you so much for your help!

Cathy
 
CathyLou said:
I have worked out the correct answer now. Thank you so much for your help!

Cathy
A pleasure :smile:
 

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