Mechanics-Angular Motion and Conservation of Energy

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SUMMARY

The discussion focuses on the mechanics of a uniform bar of mass m and length L, pivoted at one end, as it swings downward under the influence of gravity. At the horizontal position, the horizontal component of the acceleration of the free end of the bar is determined by the angular motion equations, while the vertical component of the acceleration at the midpoint is derived from the principles of rotational dynamics. The vertical force exerted by the hinge can be calculated using the moment of inertia formula, I = 0.33 * m * r^2, and the relationship between torque and angular acceleration. The participant initially misjudged the vertical acceleration, believing it to be zero, but clarified that it is indeed non-zero due to the dynamics involved.

PREREQUISITES
  • Understanding of angular motion principles
  • Familiarity with conservation of energy concepts
  • Knowledge of moment of inertia calculations
  • Basic grasp of torque and angular acceleration relationships
NEXT STEPS
  • Study the relationship between gravitational potential energy and rotational kinetic energy
  • Learn how to calculate angular acceleration using torque
  • Explore the dynamics of pivoted rigid bodies in motion
  • Investigate the effects of friction in pivot systems on motion
USEFUL FOR

Students and educators in physics, particularly those focusing on mechanics, angular motion, and energy conservation principles. This discussion is beneficial for anyone solving problems related to rotational dynamics and energy transformations.

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Mechanics--Angular Motion and Conservation of Energy

Homework Statement



A uniform bar of mass m and length L is pivoted at one end and is held vertically above the pivot. After the bar is released, it swings downward and clockwise with no friction in the pivot.

At the instant the bar is horizontal, find the magnitudes of the following quantities (use g for the acceleration of gravity): The horizontal component of the acceleration of the free end of the bar? The vertical component of the acceleration of the midpoint of the bar? The vertical component of the force exerted on the bar by the hinge?

Homework Equations


Moment of inertia = .33*m*r*r

The Attempt at a Solution


There were many other questions in this problem that I already got correct, so I left those out. I used the transfer of gravitational potential energy to rotational kinetic energy to get the angular and linear speeds, and I found the angular acceleration using torque, but I couldn't get these three parts. I feel like the acceleration of the bar in the vertical direction should be zero at this point because it's only accelerating towards the center of the circle, which is horizontal, but it's a nonzero value. Thanks for your help!
 
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"I feel like the acceleration of the bar in the vertical direction should be zero at this point because it's only accelerating towards the center of the circle, which is horizontal, but it's a nonzero value. Thanks for your help!"

Hint: Suppose the bar were released from this point, would it accelerate downward or merely remain horizontal?
 

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