Melting Lead in a Kiln: How Long Will it Take?

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Homework Help Overview

The discussion revolves around the melting of lead in a kiln, specifically focusing on the time required to melt 2 kg of lead stored at 55 degrees F when placed in a kiln at 617.5 degrees F. The problem involves thermodynamic concepts and calculations related to heat transfer and phase changes.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the need to convert temperature units from Fahrenheit to Celsius and question the relevance of the constants provided. There are attempts to calculate the energy required for melting but uncertainty about the rate of heat transfer is noted.

Discussion Status

The discussion is ongoing with participants exploring different aspects of the problem. Some have provided insights into the constants and their meanings, while others express uncertainty about the sufficiency of the given information for a complete solution.

Contextual Notes

Participants highlight the lack of information regarding the coefficient of heat transfer and the assumption of constant temperature for the steel pot. There is also mention of the need for clarity on the definitions of latent heat constants.

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Homework Statement



A girl wishes to make a lead casting of an object which will require 2kg of melted lead. if the lead was stored in her basement at approximately 55 degrees F, and it is melted to a 1/4" thick steel pot of approximate cross sectional area of 12in^2, how long will it take to melt the lead if its placed in a kiln at 617.5 degrees F, the melting point of lead?

Homework Equations



Q=mc delta t
Q=mc

Constants for lead: Lf=.25E5 J/kg Lv=8.7E5 J/kg c=130J/kgCelsius
Constants for steel: k=40 J/s times m times Celsius

The Attempt at a Solution



Q=2(130)(562.5)
Q=1.46E5
Qv=2(8.7E5)
Qv=1.74E6
Qf=2(.25E5
Qf=50000

Not sure where else to go from here...
 
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A long one to go on this I am afraid. First off your data is in Fahrenheit and your constants in celsius. What course is this--i'm thinking you have overall energy requirements posted above, but nothing about how fast the process will occur.
 
oh man...the temp units are off. a complicated problem you loose track of the basics...

I gave all of the info that i have...and its for my calc based physics class
 
Thats reassuring. To solve this will require some math. There should be some coefficient of heat transfer, etc.Not sure what Lf and all the other constants represent, the only one that I see which has a time dimension is the last.
 
lf=latent heat of fusion
lv=latent heat of vaportation?
 
Sorry, I'm not sure I can help. Someone else may be able to.

You're given a mass of lead and the shape it will become. You also know the lead is just melted and not vaporized, so know need to worry about lv. I believe the temp of the steel can be assumed to be constant, so you know exactly the number of calories it will take to make 2 Kg of solid lead to molten lead. You're given a bunch more info, but nothing else? Take an example with water--you take a liter of very cold ice and dump it into a steel pot at 0 degrees--don't you need to know something about the shape of ice block and NOT the pot, as well as rate of heat transfer. Wish I could help more, problem just doesn't have enough info imo.
 
it is alright, thank you for attempting though..
 
Any other thoughts?
 
=[...
 
  • #10
itr said:
Any other thoughts?


Wish I had.
 

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