Melting of ice with water thermodynamics problem

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SUMMARY

The discussion focuses on a thermodynamics problem involving the melting of ice in water, specifically calculating the final masses of ice and water when 0.500kg of ice at -5.00°C is mixed with 1.80kg of water at 17.00°C, resulting in a mixture at 0.00°C. The relevant equations used include Q = mcΔT for heat transfer and Q = mLf for the latent heat of fusion. The participant correctly identifies that not all ice melts, leading to the conclusion that some ice will remain unmelted, and introduces a variable for the mass of ice that does melt to establish a relationship between heat lost by the water and heat gained by the ice.

PREREQUISITES
  • Understanding of thermodynamics principles, specifically heat transfer.
  • Familiarity with specific heat capacity and latent heat concepts.
  • Ability to apply the equations Q = mcΔT and Q = mLf in calculations.
  • Knowledge of mass and temperature relationships in phase changes.
NEXT STEPS
  • Study the concept of heat transfer in phase changes, focusing on latent heat.
  • Learn how to set up and solve equations involving multiple phases of matter.
  • Explore specific heat calculations for different materials, including ice and water.
  • Investigate real-world applications of thermodynamics in climate science and engineering.
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Students and professionals in physics, engineering, and environmental science who are looking to deepen their understanding of thermodynamics and heat transfer principles, particularly in phase change scenarios.

Satis24
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1. 0.500kg of ice at -5.00°C is put into a vessel containing 1.80kg of water at 17.00°C and mixed together, the result being a mixture of ice and water at 0.00°C. Calculate that final masses of ice and water, taking the water equivalent of the vessel as 0.148kg, the specific heat of ice as 2.04kJ/kg*K, and the latent heat of fusion of ice as 335kJ/kg
2. Q = mcΔT and Q = mLf
3. I started by finding Q = mLf of the ice. Q = (0.500kg)*(335kJ/kg*K) = 167.5kJ However I wasn't sure exactly sure where to go from here. I know that the mass of the vessel has to be added into the mass of ice at come point, but I'm really unsure of where to go from here.
 
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Satis24 said:
I started by finding Q = mLf of the ice. Q = (0.500kg)*(335kJ/kg*K) = 167.5kJ
But the question implies not all the ice melts, so the above number is too high.
In general, there are three possible end states:
- the ice warms but none melts
- some but not all of the ice melts
- all of the ice melts
You're told all ends up at 0C, so you can safely assume the middle case.
Introduce a variable unknown for the mass of ice that does melt. Using that, write an equation relating the heat lost by the water and the vessel to that taken up by the ice. Can you calculate those two quantities?
 
Yes I should be able to figure that out, thank you!
 

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