Messing up my algebra seriously i need to re-learn my algebra

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SUMMARY

The discussion centers on the simplification of the algebraic expression \(\frac{(3x^2 - 6x)}{3((x^3 - 3x^2)^{2/3})}\). The user attempted to simplify the expression but encountered errors, particularly in the factorization of the denominator. Key insights include the importance of correctly applying exponent rules and the distinction that \((a+b)^c \neq a^c + b^c\) in general. The suggestion to factor the denominator is crucial for accurate simplification.

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messing up my algebra... seriously... i need to re-learn my algebra...

The Attempt at a Solution



ok so i have.
((3x^2)-6x)/(3((x^3)-(3x^2))^(2/3))

and i simplified it too.
((3x^2)-6x)/(3((x^(5/3))-(3x^(4/3))^(2/3))

then further simplified it too.
(3x(x-2))/(3x(x^(2/3))-(3x^(1/3)))

then got
((x-2))/((x^(2/3))-(3x^(1/3)))

i found out that i am doing it wrong but i don't know what...

Thank You ahead of time. Thank You.
 
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I've no idea what you've done form line 1 to line 2. However, [tex](a+b)^c\neq a^c+b^c[/tex], in general.

I would start by factorising the terms in the denominator.
 


The most problematic part of solving this would be when factorising the denominator:

Generally, [tex](ax+bx)^n = (x[a+b])^n = x^n(a+b)^n[/tex]
 

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