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Messing up my algebra seriously i need to re-learn my algebra

  1. Dec 5, 2008 #1
    messing up my algebra.... seriously... i need to re-learn my algebra...

    3. The attempt at a solution

    ok so i have.
    ((3x^2)-6x)/(3((x^3)-(3x^2))^(2/3))

    and i simplified it too.
    ((3x^2)-6x)/(3((x^(5/3))-(3x^(4/3))^(2/3))

    then further simplified it too.
    (3x(x-2))/(3x(x^(2/3))-(3x^(1/3)))

    then got
    ((x-2))/((x^(2/3))-(3x^(1/3)))

    i found out that i am doing it wrong but i dont know what...

    Thank You ahead of time. Thank You.
     
  2. jcsd
  3. Dec 5, 2008 #2

    cristo

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    Staff Emeritus
    Science Advisor

    Re: messing up my algebra.... seriously... i need to re-learn my algebra...

    I've no idea what you've done form line 1 to line 2. However, [tex](a+b)^c\neq a^c+b^c [/tex], in general.

    I would start by factorising the terms in the denominator.
     
  4. Dec 5, 2008 #3

    Mentallic

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    Homework Helper

    Re: messing up my algebra.... seriously... i need to re-learn my algebra...

    The most problematic part of solving this would be when factorising the denominator:

    Generally, [tex](ax+bx)^n = (x[a+b])^n = x^n(a+b)^n[/tex]
     
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