Prove It Gold Member MHB Messages 1,434 Reaction score 20 Sep 24, 2021 #2 It might be worth evaluating each line in their vector forms, and then seeing if you can find where they intersect.
It might be worth evaluating each line in their vector forms, and then seeing if you can find where they intersect.
mrtwhs Messages 47 Reaction score 0 Oct 15, 2021 #4 Although $\dfrac{x}{1} = \dfrac{y}{2} = \dfrac{z}{3}$ is a line, $3\beta^2x+3(1-2\alpha)y+z=3$ is not. It is a plane.
Although $\dfrac{x}{1} = \dfrac{y}{2} = \dfrac{z}{3}$ is a line, $3\beta^2x+3(1-2\alpha)y+z=3$ is not. It is a plane.