MHB Mil.navy.01 completing the square

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The discussion focuses on rewriting the equation \(x^2 - 4x + 3 = 0\) using the method of completing the square. The correct transformation leads to \((x-2)^2 = 1\), which matches option b from the multiple-choice answers. Participants clarify that the problem does not suggest a specific transformation but rather presents options, with only one being correct. The steps involve isolating the quadratic expression, completing the square, and simplifying to find the solution. Ultimately, the correct form is confirmed as \((x-2)^2 = 1\).
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$\tiny{mil.navy.01}$
This is on an sample entrance exam test for the Navy Academy

Use "completing the square" to rewrite
$x^2-4x+3=0$ in the form $\quad (x-c)^2=d$
a, $(x-1)^2=1$
b. $(x-2)^2=1$
c. $(x-3)^2=1$
d. $(x-2)^2=2$
e. $(x-4)^2=1$

ok I am not sure why they suggest the second transformation
 
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$$x^2-4x+3 = 0\\
(x-2)^2 -4 + 3 = 0\\
(x-2)^2 = 1$$

I don't think the problem is suggesting anything.
Those are multiple choice answers only one of which is correct.
 
$x^2-4x+3=0$
isolate
$x^2-4x=-3$
add 4 to both sides
$x^2-4x+4=-3+4$
simplify
$(x-2)^2=1$
 
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Obviously, there is something elementary I am missing here. To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix in the real plane; taking the transpose we get which then corresponds to a-bi...

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