Min weight of elevator accelerating, constant velocity, decelerating

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SUMMARY

The discussion focuses on calculating the minimum scale reading for Liz in an elevator during its trip between floors. The elevator accelerates uniformly from the 1st to the 2nd floor and decelerates uniformly from the 5th to the 6th floor, with a constant velocity between the 2nd and 5th floors. Using the equation N + Ma = Mg for acceleration and N - Ma = Mg for deceleration, Liz's mass is determined to be 8 kg, leading to a minimum scale reading of 800 N when the elevator is stationary.

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  • Ability to solve equations involving forces and mass
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Homework Statement



Starting from rest, an elevator accelerates uniformly between the 1st and 2nd floors, and decelerates uniformly between the 5th and 6th floors, coming to a stop at the 6th floor. Between the 2nd and 5th floors, the elevator covers the 6 meter distance between each two adjacent floors in 1 second. Inside, Liz (who is about to graduate) is standing on a scale that reads 800 N when the elevator isn't moving. What was her minimum scale reading during the trip? Use g = 10 m/s^2.

Homework Equations


The Attempt at a Solution



From 1st floor to second floor the equation would be [tex]N + Ma = Mg.[/tex]
From second floor to fifth, it moves with constant velocity i.e 6 m/s
From fifth to sixth, the equation would be [tex]N - Ma= Mg.[/tex]

Here, from the given data in question M = 8kgs.
How do I find the minimum reading?
 
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Never mind. Was making a silly mistake. Got it.
 

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