Min weight of elevator accelerating, constant velocity, decelerating

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Homework Statement



Starting from rest, an elevator accelerates uniformly between the 1st and 2nd floors, and decelerates uniformly between the 5th and 6th floors, coming to a stop at the 6th floor. Between the 2nd and 5th floors, the elevator covers the 6 meter distance between each two adjacent floors in 1 second. Inside, Liz (who is about to graduate) is standing on a scale that reads 800 N when the elevator isn't moving. What was her minimum scale reading during the trip? Use g = 10 m/s^2.

Homework Equations


The Attempt at a Solution



From 1st floor to second floor the equation would be [tex]N + Ma = Mg.[/tex]
From second floor to fifth, it moves with constant velocity i.e 6 m/s
From fifth to sixth, the equation would be [tex]N - Ma= Mg.[/tex]

Here, from the given data in question M = 8kgs.
How do I find the minimum reading?
 
on Phys.org
Never mind. Was making a silly mistake. Got it.