Minimum amount of friction in a turn

  • Thread starter Thread starter TheronSimon
  • Start date Start date
  • Tags Tags
    Friction Minimum
Click For Summary

Homework Help Overview

The discussion revolves around determining the minimum coefficient of friction required for a truck to navigate an unbanked curve. The problem involves a truck with a mass of 3700 kg, a curve radius of 25 m, and a speed of 45 km/h.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of a formula for the minimum coefficient of friction and question the accuracy of substitutions made in the calculations. There is a focus on unit conversion and the interpretation of variables in the formula.

Discussion Status

The conversation is ongoing, with participants providing hints and corrections regarding the calculations. There is a lack of consensus on the correct substitution values and the interpretation of the formula components, indicating a productive exploration of the problem.

Contextual Notes

Participants are addressing potential misunderstandings related to unit conversions and the mathematical operations involved in the formula. There is an emphasis on ensuring that the calculations align with standard units and proper mathematical principles.

TheronSimon
Messages
37
Reaction score
0

Homework Statement


What minimum coefficient of friction between the tires and the road will allow a 3700 kg truck to navigate an unbanked curve of radius 25 m at a speed of 45 km/h?



Homework Equations





The Attempt at a Solution


The minimum coefficient is 7.62. To arrive at this i used the formula k(min)=(V2/(gr)). This will be substituted to 252/(3700/45).
 
Physics news on Phys.org
Your formula is correct, but your substitution is not. Hint: Convert the speed to standard units of m/s.
 
so instead put in 12.5, and then 625/296 = 2.11 ?
 
Last edited:
TheronSimon said:
so instead put in 12.5, and then 625/296 = 2.11 ?
No. Where do the numbers 625 and 296 come from?
 
well 25^2 is 625 and 3700/12.5 is 296
 
TheronSimon said:
well 25^2 is 625 and 3700/12.5 is 296
You need to evaluate: (V2)/(gr)

No need to square 25 or involve 3700.
 
you lost me now, why would i square V^2? :(
 
TheronSimon said:
you lost me now, why would i square V^2? :(
See your first post. (You need to evaluate V^2, which is V squared.)
TheronSimon said:
To arrive at this i used the formula k(min)=(V2/(gr)).
 
but i thought it would only SQRT if both sides have an exponent of 2 to get rid of the 2, because what i do to one side i have to do to the other do i not?
 

Similar threads

Replies
3
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 3 ·
Replies
3
Views
22K
Replies
1
Views
4K
  • · Replies 5 ·
Replies
5
Views
10K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
3K