MIT online lecture: Algebra error?

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SUMMARY

The discussion centers on a perceived error in an MIT online lecture on calculus, specifically regarding the calculation of the area of a triangle. The lecturer presented the equation 1/2 times (2x0)(2y0) and concluded it equaled 2. However, the participant's calculations yield 2x0y0, indicating a misunderstanding of how x0 and y0 cancel out. The key to resolving this discrepancy lies in the relationship defined by the curve equation y=1/x, which affects the values of x0 and y0.

PREREQUISITES
  • Understanding of basic calculus concepts, particularly derivatives.
  • Familiarity with the area calculation for geometric shapes, specifically triangles.
  • Knowledge of algebraic manipulation and simplification of expressions.
  • Basic understanding of curve equations and their implications in calculus.
NEXT STEPS
  • Review the MIT lecture on derivatives, focusing on the area of triangles.
  • Study the implications of the equation y=1/x in relation to area calculations.
  • Practice algebraic simplification techniques to understand variable cancellation.
  • Explore additional resources on calculus concepts related to geometric interpretations.
USEFUL FOR

Students of calculus, educators teaching mathematical concepts, and anyone interested in understanding geometric area calculations in relation to algebraic expressions.

Reagan0mics
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Okay so I was watching this lecture.

http://ocw.mit.edu/courses/mathemat...ll-2006/video-lectures/lecture-1-derivatives/

Skip to 41 minutes

He's solving the area for a triangle, and I think he got the answer wrong.

The equation he got was

1/2 times (2x0)(2y0)

Some how he got this equation to = 2

However when I do it, the answer I get is 2x0y0

Because I do this:

1/2 times (2x0)(2y0)

4x0y0/2

which then is the same as 2x0y0
Some how he got 2 though as his answer. Am I missing some piece of information or something? I have no clue how he got the x0 and y0 to cancel out.
 
Mathematics news on Phys.org
The clue lies in the equation of the curve. We have y=1/x, so then what does xy equal?
 

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