Mixed Inhibition: Finding Ki & Ks Relation

[Dassinia]

Homework Statement

I have this mixed inhibition, and knowing that it is a thermodynamic cycle i am asked to find the relation between the different Ki and Ks.
https://scontent.xx.fbcdn.net/hphotos-xfp1/v/t35.0-12/12699252_1024216030972374_1605707906_o.jpg?oh=8b60ba8c953ea368fe8fc09af6fe5eaa&oe=56C77997

Homework Equations

The Attempt at a Solution

I am not even sure to understand the question...

 

[epenguin]

Homework Statement

I have this mixed inhibition, and knowing that it is a thermodynamic cycle i am asked to find the relation between the different Ki and Ks.
https://scontent.xx.fbcdn.net/hphotos-xfp1/v/t35.0-12/12699252_1024216030972374_1605707906_o.jpg?oh=8b60ba8c953ea368fe8fc09af6fe5eaa&oe=56C77997
2. Relevant equation

The Attempt at a Solution

I am not even sure to understand the question...

Look at the top line only. What is the equilibrium constant between E and ES?
Well okay since you say you don't understand the question K_s = [E][ S]/[ES] = ?

Now rub out to the arrows of the top line. Leave the others. What is the above-defined equilibrium constant equal to?

Can these equilibrium constants be different?

 

[Dassinia]

Look at the top line only. What is the equilibrium constant between E and ES?
Well okay since you say you don't understand the question K_s = [E][ S]/[ES] = ?

Now rub out to the arrows of the top line. Leave the others. What is the above-defined equilibrium constant equal to?

Can these equilibrium constants be different?

Between E and ES Ks=k_-1/k₁ Is it equal to k'_-1/k'₁=Ks' ?

 

[epenguin]

Between E and ES Ks=k_-1/k₁ Is it equal to k'_-1/k'₁=Ks' ?

In general no.

Rub out to the arrows of the top line. Leave the others. In fact just write out the scheme again without the k₁, k_-1 steps. Can't you work out what that gives you for [E][ S]/[ES] ?