- #1

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^{2}- h for P. I understand partial fractions are needed and I have already solved dP/dt = k P - A P

^{2}. Is anyone able to solve it, Cheers NZBRU.

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- Thread starter NZBRU
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- #1

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- #2

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dt = dP/(k P - A P＾2 - h) = -1/A dP/[ (P- k/A)^2-{(k/A)^2+h} ] = -1/A dp/[p^2 - {(k/A)^2+h}) ] , p= P- k/A

= -1/A dp/[p - sqrt{(k/A)^2+h} ][p +sqrt {(k/A)^2+h} ]

now you can integrate.

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