- #1

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For example this:

Starting with this equation for pressure:

##P=ρgh## ; ## h = -y##

##P= -ρgy##

taking the derivative of this as ##Δy→0## we get

##\frac {dP} {dy} = -ρg##

and to solve this we'd normally go

##dP = -ρg dy##

What i'm wondering is what would happen if we were to now divide each side by a differential like lets say dt to get:

## \frac {dP} {dt} = -ρg \frac {dy} {dt} ##

how would we end up solving this since we now essentially have two different "derivatives" on each side? would we just simply continue integrating each side through normally to obtain the functions P(t) and y(t) or would this instead be considered a PDE? in the form

## \frac {\partial P} {\partial t} = -ρg \frac {\partial y} {\partial t} ##