Molecular weight of lead(ii) nitrate Pb(NO_3)_2

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SUMMARY

The molecular weight of lead(II) nitrate, Pb(NO3)2, is definitively calculated to be 331.2 g/mol, contrary to the 283.2 g/mol stated in the book "Analytical Chemistry" (7th edition) by Gard D. Christian. The discrepancy arises from an incorrect molar mass calculation in the book, which appears to have mistakenly calculated the mass for PbN2O3, omitting the correct contribution from the three oxygen atoms. This error has been consistently replicated across various online resources.

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Paul Black
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Hello everyone
I am trying to solve the following question from the book Analytical Chemistry 7th edition by Gard D. Christian - Page 164 Example 5.17
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My problem is when I calculate the molecular weight of Pb(NO_3)_2 I get 331.2 g/mol but in the book they get 283.2 g/mol . Could you explain to me where they get this number. So instead of getting 0.137 g as last result, I get 0.16 g.

Also googling the question always gets me the same solution.
 
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Paul Black said:
when I calculate the molecular weight of Pb(NO_3)_2 I get 331.2 g/mol

That's what I got as well, book is wrong.
 
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First time I see an error in a book.
So in that case all the internet pages that have the same question+solution made the same mistake. Do they just copy past ?
 
Paul Black said:
First time I see an error in a book.

Lucky you.

So in that case all the internet pages that have the same question+solution made the same mistake. Do they just copy past ?

Apparently.

The molar mass they used is off by 48, which is exactly three oxygen atoms, as if they had calculated molar mass for PbN2O3.
 
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Thank you for your help
Will see if this book has more mistakes.
 

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