flash
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The moment of inertia of a sphere rotating about the centre is (2/5)mr^2, but what if it has a hollow 'core'?
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The moment of inertia of a hollow sphere can be calculated by integrating the mass distribution, specifically using the formula r2dm. For a hollow spherical shell with an inner radius, the moment of inertia is determined by summing the moments of inertia of the inner and outer spheres. The discussion emphasizes the importance of defining the inner radius and the thickness of the shell when calculating the moment of inertia. Participants recommend utilizing integration techniques and understanding the density of the outer part to arrive at the correct solution.
PREREQUISITESStudents and professionals in physics, particularly those studying mechanics and rotational dynamics, as well as engineers working with materials that involve hollow spherical structures.
flash said:Sorry, I should have been clearer. There is an inner radius involved, so the thickness is not negligable. I know the basic idea of integration to find the moment of inertia, r^2dm, but haven't done much of it.
dextercioby said:A (2-)sphere is hollow to begin with. So your question doesn't make too mush sense.
Daniel.
flash said:Thanks for all the replies. I only know the mass of the outer part of the sphere. Here's what I think I will do: Find the density of the outer part, calculate the moment of inertia of the solid sphere with this density and subtract the moment of inertia of the inner sphere with this density. Will that work?
OlderDan said:Therefore the volume of a sphere is zero. Even mathematicians resort to "common usage" when it serves their purpose. I've never heard anybody say "the volume of the region bounded by a shpere of radius R" is . . . .
We of course are making the same mistake when we talk about the area of a circle. Using its formal definition, it has none.