Moment of Inertia of Half a Sphere

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SUMMARY

The moment of inertia of a half sphere is calculated using the formula I_a = I_G + md^2, where I_G is the moment of inertia about the center of mass. For a hemisphere, I_G is defined as 0.259mr^2, and the distance d from the center to the axis is (3r/8). The calculation leads to I_a = 0.259mr^2 + m(3r/8)^2, which simplifies to 2mr^2/5. However, this contradicts the professor's assertion that I_a should equal mr^2/5, indicating a misunderstanding of the parallel axis theorem and the definition of moment of inertia.

PREREQUISITES
  • Understanding of the parallel axis theorem
  • Knowledge of moment of inertia concepts
  • Familiarity with the formula for the moment of inertia of a hemisphere
  • Basic principles of rotational dynamics
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  • Review the derivation of the moment of inertia for various shapes, including hemispheres
  • Study the parallel axis theorem in detail
  • Explore examples of calculating moment of inertia for composite bodies
  • Investigate the physical significance of moment of inertia in rotational motion
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theBEAST
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Homework Statement


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Homework Equations


I_a = I_G + md^2

The Attempt at a Solution


I tried using the parallel axis theorem to find the moment of inertia about the axis.

In the formula sheet they give the moment of inertia of a hemisphere:
I_G = 0.259mr^2, where d, the distance from the center is equal to (3r/8).

Thus to find the inertia about the axis we will have to solve
I_a = 0.259mr^2 + m(3r/8)^2

This ends up giving me 2mr^2/5 which is not the answer... However I still think this is the correct answer. This is because I_a = mr^2/5 = 0.2mr^2 (which is the answer according to the prof) is less than the moment at the center I_G = 0.259mr^2. According to the parallel axis equation I_a = I_G + md^2, I_a must be larger than I_G not smaller...
 
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Go back to the definition of the moment of inertia. What is the moment of inertia of a point mass, at distance R from the rotation axis? What if you have two identical point masses at the opposite ends of a diameter?

Your problem is connected to "m". What is it?

ehild
 
Last edited:

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