Momentum and Pressure and Forces

Click For Summary
The discussion revolves around the relationship between force, pressure, and velocity, highlighting a perceived contradiction in the formulas. The user presents two equations: one suggesting that force is proportional to the square of velocity and another indicating direct proportionality to velocity. Clarifications reveal that F/A is proportional to v², not force itself, and emphasize the importance of understanding the dot product in work calculations. The conversation concludes with a note on formatting using LaTeX, which enhances the presentation of mathematical expressions. Overall, the thread effectively addresses the theoretical confusion surrounding these fundamental physics concepts.
Pawnag3
Messages
8
Reaction score
0
This is a theoretical question that I have, it might be somewhat elementary, or I might be missing something. Basically, we have two formulas:
1) We know that
P = F/A
By multiplying by d/d, we get:
P = Work/Volume
P = Energy/Volume
P = 1/2 mv2 / V
Therefore
F/A = 1/2 mv2 / V
And therefore, the force is equal to the velocity squared.
2) However, according to F*t = mv
We say that Force is directly proportional to velocity.

Do you see the contradiction?
Please Help

Note: I'm basically comparing the relationship of force with respect to velocity
 
Physics news on Phys.org
Pawnag3 said:
F/A = 1/2 mv2 / V
And therefore, the force is equal to the velocity squared.
2) However, according to F*t = mv
We say that Force is directly proportional to velocity.

Do you see the contradiction?

in the first sentence
<br /> \frac{F}{A}=\frac{1}{2}\frac{mv^2}{V}<br />
Now when you bring the area on the other side A/V becomes 1/length or 1/distance and cancels with one (length)2 of velocity ... hence there is only one velocity term left and hence F proportional to v.

Another mistake is you have considered F*d=Work but actually its the dot product between them.

Rem: F/A is proportional to v2 not force!
 
Umm, thanks, that clarifies everything :D
But I have one question:
1) How did you make the formatting look so nice? :D
I couldn't figure it out (but then again, I didn't spend too much time, under which heading is it? :P)
 
Pawnag3 said:
Umm, thanks, that clarifies everything :D
But I have one question:
1) How did you make the formatting look so nice? :D
I couldn't figure it out (but then again, I didn't spend too much time, under which heading is it? :P)

I used latex or tex as its called ... you can learn it here
https://www.physicsforums.com/showthread.php?t=386951
 
Last edited by a moderator:
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 9 ·
Replies
9
Views
1K
Replies
335
Views
15K
  • · Replies 23 ·
Replies
23
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
464
  • · Replies 27 ·
Replies
27
Views
940
Replies
19
Views
3K