A circus cannon, which has a mass M = 5000 kg, is tilted at q = 40°. When it shoots a projectile at v0 = 80 m/s with respect to the cannon, the cannon recoils along a horizontal track at vcannon = 1 m/s with respect to the ground.
1. At what angle to the horizontal does the projectile move with respect to the ground?
The Attempt at a Solution
In order to solve this first question, I first found the horizontal velocity of the ball. 80cos(40) gives me about 61.xxx m/s. The cannon recoils in the opposite direction, so I add 1 m/s. I then use arccos(62.xxx/80) to find the new angle with respect to the ground. This is not the correct answer. I'm not sure what to do.