Momentum, Impulse and Collisions

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SUMMARY

This discussion focuses on the application of momentum and impulse in two physics problems involving collisions. The first problem calculates the recoil velocity of a 79-kg skater after an 86-kg skater pushes off with a velocity of 2.4 m/s, resulting in a recoil velocity of 2.613 m/s. The second problem involves a 5-g marble that rebounds after hitting the floor, with calculations revealing a change in momentum and an impulse of 6260 N when the marble is in contact with the floor for 2.5 ms.

PREREQUISITES
  • Understanding of momentum conservation principles
  • Familiarity with impulse and its relation to force and time
  • Basic knowledge of physics equations related to collisions
  • Ability to perform calculations involving mass and velocity
NEXT STEPS
  • Study the conservation of momentum in two-body collisions
  • Learn about impulse-momentum theorem applications
  • Explore the effects of varying contact time on force calculations
  • Investigate real-world examples of momentum transfer in sports
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of momentum and impulse in real-world scenarios.

xRohan1
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Homework Statement


Two hockey players push each other on the ice. The 86-kg skater moves with a velocity of 2.4 m/s. Find the recoil velocity of the 79-kg skater

Homework Equations


idk

The Attempt at a Solution


86*2.4=79*v2 v2=2.613 m/s

Second problem

Homework Statement


A child drops a 5-g marble on the floor. The marble hits the floor with a velocity of -3.13m/s and rebounds with a velocity of 1.87 m/s. What is the marble's change in momentum? What impulse acts on the marble? What is the force of impact if the marble is in contact with the floor for a time of 2.5 x 10^-3s?

Homework Equations


idk

The Attempt at a Solution


A) (5*1.87)-(5*-3.13)
B)
C)(5*-3.13)/(2.5*10^-3)=-6260N
 
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xRohan1 said:

Homework Equations


idk
Can you not express the principle you used below in general terms?
xRohan1 said:
A) (5*1.87)-(5*-3.13)
Units?
xRohan1 said:
B)
Are you stuck on this?
xRohan1 said:
C)(5*-3.13)/(2.5*10^-3)=-6260N
You need to use the result from A/B
 

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