Momentum must be conserved, so this is true, right?

  • Thread starter Thread starter StephenDoty
  • Start date Start date
  • Tags Tags
    Momentum
StephenDoty
Messages
261
Reaction score
0
True or False:
In a collision between a light hydrogen molecule and a heavy water molecule, the momentum lost by one molecule is exactly the same as the momentum gained by the other molecule.

Momentum must be conserved, so this is true, right?
 
on Phys.org
In physics, momentum is always conserved. You just have to think about two things. A) Is the system being considered closed? and B) What happens as a result of momentum conservation.
 
It seems to be a closed system to me

so isn't the momentum conserved making this true


so i can make sure I have this concept:
as a stone slides down a frictionless hill its mechanical energy is conserved but its momentum is not. true or false

well since we are not given any info on the velocity at the beginning or end and since the velocity is constantly changing we cannot make any assumptions about momentum thus this statement is true.
 
Last edited:
Well we know velocity is increasing, and p=mv, so momentum is increasing. Like I said, momentum is always conserved, so an equal amount has to come from somewhere else.
 
so the first one is true and the second one is false?
 
Nabeshin said:
Like I said, momentum is always conserved, so an equal amount has to come from somewhere else.
Momentum is not always conserved. Momentum is conserved in a closed system, but not in an open system (i.e., one with external forces acting on it).
 
Hi StephenDoty,

Both of your true/false statements are true. As the stone slides down the hill, its momentum increases, so its momentum is not conserved.

Deciding on whether momentum is conserved or not depends critically on what your system is. If there are no forces on the system from outside the system, then momentum is conserved. If there is a net force acting on the system from the outside, then the momentum will change with time.

So for the stone going down the hill, the wording of the question means that we want to consider the stone by itself as the system. There is a net outside force (the force from the earth), so momentum is not conserved for the stone.

Momentum is conserved if we had chosen (stone+earth) as a system. The change in the stone's momentum is equal in magnitude and opposite in direction to the change in the Earth's momentum. (The Earth pulls on the stone and the stone pulls on the earth, in addition to the action/reaction normal forces between stone and hill.) The momentum of (stone+earth) is conserved as the stone slides down the hill.
 
good i have the concept then

thank you
 

Similar threads

Replies
17
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
23
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
14K
  • · Replies 21 ·
Replies
21
Views
4K
Replies
21
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
Replies
5
Views
2K