Momentum must be conserved, so this is true, right?

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Homework Help Overview

The discussion revolves around the conservation of momentum in collisions, specifically between a light hydrogen molecule and a heavy water molecule. Participants explore the implications of momentum conservation in both closed and open systems, as well as the relationship between momentum and mechanical energy in different scenarios.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants examine whether momentum is conserved in a given scenario, questioning the definitions of closed and open systems. They also discuss the implications of changing velocities on momentum and the conditions under which momentum conservation holds true.

Discussion Status

The discussion is active, with participants providing insights into the conditions for momentum conservation. Some clarify that momentum is conserved in closed systems while others explore the effects of external forces. There is recognition of differing interpretations regarding the conservation of momentum in various contexts.

Contextual Notes

Participants note the lack of specific information regarding initial and final velocities in the scenarios discussed, which affects their ability to make definitive conclusions about momentum conservation. The distinction between closed and open systems is a central theme in the conversation.

StephenDoty
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True or False:
In a collision between a light hydrogen molecule and a heavy water molecule, the momentum lost by one molecule is exactly the same as the momentum gained by the other molecule.

Momentum must be conserved, so this is true, right?
 
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In physics, momentum is always conserved. You just have to think about two things. A) Is the system being considered closed? and B) What happens as a result of momentum conservation.
 
It seems to be a closed system to me

so isn't the momentum conserved making this true


so i can make sure I have this concept:
as a stone slides down a frictionless hill its mechanical energy is conserved but its momentum is not. true or false

well since we are not given any info on the velocity at the beginning or end and since the velocity is constantly changing we cannot make any assumptions about momentum thus this statement is true.
 
Last edited:
Well we know velocity is increasing, and p=mv, so momentum is increasing. Like I said, momentum is always conserved, so an equal amount has to come from somewhere else.
 
so the first one is true and the second one is false?
 
Nabeshin said:
Like I said, momentum is always conserved, so an equal amount has to come from somewhere else.
Momentum is not always conserved. Momentum is conserved in a closed system, but not in an open system (i.e., one with external forces acting on it).
 
Hi StephenDoty,

Both of your true/false statements are true. As the stone slides down the hill, its momentum increases, so its momentum is not conserved.

Deciding on whether momentum is conserved or not depends critically on what your system is. If there are no forces on the system from outside the system, then momentum is conserved. If there is a net force acting on the system from the outside, then the momentum will change with time.

So for the stone going down the hill, the wording of the question means that we want to consider the stone by itself as the system. There is a net outside force (the force from the earth), so momentum is not conserved for the stone.

Momentum is conserved if we had chosen (stone+earth) as a system. The change in the stone's momentum is equal in magnitude and opposite in direction to the change in the Earth's momentum. (The Earth pulls on the stone and the stone pulls on the earth, in addition to the action/reaction normal forces between stone and hill.) The momentum of (stone+earth) is conserved as the stone slides down the hill.
 
good i have the concept then

thank you
 

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