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Momentum problem: object struck with stick

  1. Oct 15, 2013 #1
    1. The problem statement, all variables and given/known data

    A stationary 1.67 kg object is struck by a stick. The object experiencees a horizontal force given by F = at - bt^3, where t is the time in milliseconds from the instant the stick first contacts the object. if a = 1500 N/ms and b = 20 N / ms^3, what is the speed of the object just after it comes away from the stick (t = 2.74 ms)?


    2. Relevant equations



    3. The attempt at a solution

    I integrated to come up with the impulse J_x. Then I added it to p_0 = 0. The integral solved at the limits of 0 to 0.00274 = 0.005631. I divided this by the mass 1.67 to get the velocity. This gave v = 0.003372 which is not right...

    What did I do wrong?

    Thanks
     
  2. jcsd
  3. Oct 15, 2013 #2

    CWatters

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    Science Advisor
    Homework Helper

    I'm rusty but shouldn't you divide by the mass before integrating or doesn't that make a difference?

    Newton says

    Force = mass * acceleration
    so
    acceleration = force / mass

    Then integrate to give velocity.
     
  4. Oct 15, 2013 #3
    I'm integrating to get an impulse, then using it to get velocity from the momentum equation. The problem is about momentum.
     
  5. Oct 15, 2013 #4

    Doc Al

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    Staff: Mentor

    Units. I suspect that you converted to seconds, when the equation was meant to be in ms.
     
  6. Oct 15, 2013 #5
    I integrated with limits of 0 to 0.00274, so it's in seconds. So that result should be J_x, and dividing out mass should give velocity. I don't see where I could have messed up units, offhand.
     
  7. Oct 15, 2013 #6

    Doc Al

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    Staff: Mentor

    Yes, but the t in the equation is in ms. Look at the units of the parameters a & b.

    For you to use seconds you must first convert the equation to use seconds. (Or just stick to ms.)
     
  8. Oct 15, 2013 #7
    Thank you.
     
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