Momentum Ratio: Why is it Wrong?

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Homework Help Overview

The discussion revolves around the calculation of momentum ratios and kinetic energy in a physics context, specifically comparing the momenta of a cardinal and a baseball. The original poster attempts to understand why their initial calculation of the momentum ratio is incorrect, despite knowing that the kinetic energies are equal.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the correct formulation of momentum and kinetic energy equations, highlighting the need for distinct variables for different velocities. There is an exploration of how to derive the velocity ratio from the kinetic energy equations.

Discussion Status

Some participants have provided guidance on maintaining algebraic forms rather than substituting numerical values too early in the process. There is ongoing exploration of simplification techniques and the implications of variable assumptions.

Contextual Notes

Participants note the importance of correctly identifying variables and the potential pitfalls of assuming equal velocities in the momentum ratio calculation. The discussion reflects a learning process with various interpretations being explored.

David112234
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Homework Statement



physicshomework.jpg

Homework Equations



KE = 1/2 M V2
P = M V

The Attempt at a Solution



p = mv
pcardinal = .0450vcardinal
pbaseball= .144vbaseball

0450vcardinal/144vbaseball
Why is this not the correct answer?

I know KE are equal so
KEcardinal= ½ .0450 v2
KEbaseball= ½ .144 v2

so .0450 v2 = .144 v2
how is knowing the KE are equal any helpful, and why is my original answer not right?
 
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Yes, the ratio of the momenta is mcardvcard/(mbasevbase), but you do not know what those velocities are. In your attempted answer you seem to have assumed they are the same.
In your KE equations you even used v for both velocities, ending up with a statement that is clearly not true.
Write the KE equations again, being careful to use different variables for the two velocities, and use them to find the velocity ratio.
 
haruspex said:
Yes, the ratio of the momenta is mcardvcard/(mbasevbase), but you do not know what those velocities are. In your attempted answer you seem to have assumed they are the same.
In your KE equations you even used v for both velocities, ending up with a statement that is clearly not true.
Write the KE equations again, being careful to use different variables for the two velocities, and use them to find the velocity ratio.

I know KE are equal so
KEcardinal= ½ .0450 vcardinal2
KEbaseball= ½ .144 vbaseball2

.0450 = vbaseball2
______ _________
.144 = vcardinal2
 
and now I take the square root to find vc/vbb and plug that into
mvc/mvbb ?
 
David112234 said:
and now I take the square root to find vc/vbb and plug that into
mvc/mvbb ?
Yes. (But it is better technique to keep everything algebraic, only plugging in numbers at the final step. This has many advantages.)
 
haruspex said:
Yes. (But it is better technique to keep everything algebraic, only plugging in numbers at the final step. This has many advantages.)

mc*√mbb
-------------------------------------
mbb*√mc

.0450√.144 / .144√.0450

Is this correct?
 
David112234 said:
mc*√mbb
-------------------------------------
mbb*√mc

.0450√.144 / .144√.0450

Is this correct?
Yes, but you can simplify that a little. I would move everything inside the square root function.
 
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haruspex said:
Yes, but you can simplify that a little. I would move everything inside the square root function.

√.002025*.144/ √.020736*.0450 = .5590169944
I put it in and it is correct. thank you
 
David112234 said:
√.002025*.144/ √.020736*.0450 = .5590169944
I put it in and it is correct. thank you
ok!
But I meant, simplify it while still in algebraic form. Never plug numbers in until the final step. Many advantages to be had.
 
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