Monotonicity of convex function

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The discussion centers on proving the monotonicity of convex functions, specifically that if a convex function f: (a, ∞) → R satisfies f(x2) > f(x1) for x2 > x1, then it must also hold that f(x4) ≥ f(x3) ≥ f(x2) for all x3 > x2 and x4 > x3. This establishes that a convex function is either decreasing throughout its domain or begins increasing from a certain point onward. The proof does not rely on the differentiability of the function, emphasizing the fundamental properties of convexity.

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hellbike
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f:(a,\infty)->R
i want to prove, that, if function is convex, then:

if exist x_1 \in R, exist x_2>x_1 : f(x_2)>f(x_1)
then:
for all x_3>x_2 for allx_4>x_3 : f(x_4)\ge f(x_3)\ge f(x_2)

in other words:
convex function is either decreasing on whole domain, or it starts to increase from some point and then is increasing from that point to the end of domain

We don't assume that function is differential.

With assumption that f(x_2)>f(x_1) i should get something from definition of convex function, but i don't know how to do it.

I'm asking for some tip.
 
Last edited:
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First show that convex implies this: If a < b < c, then
<br /> \frac{f(b)-f(a)}{b-a} \le \frac{f(c)-f(b)}{c-b}<br />
 

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