Moon revolution period 27.32, but got 27.53 from equation?

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SUMMARY

The calculated Moon revolution period using the formula T = sqrt(4π^2 * R^3/(GM)) yields a result of 27.53 days, while the expected value is 27.32 days. This discrepancy arises from the simplification of the orbit as circular and not accounting for the gravitational influence of the Earth on the Moon. By incorporating the mass of the Moon into the equation, the revised period is calculated as 27.36 days, which is closer to the expected value but still contains minor errors likely due to rounding and the Earth's own motion during the lunar month.

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Hello,

I'm trying to calculate Moon revolution period but always got 27.53 instead of 27.32.
G = 6.674e-11 (m^3 kg^-1 s^-2)
M = 5.9724e24 (kg) from http://nssdc.gsfc.nasa.gov/planetary/factsheet/moonfact.html
R = 384400000 (m) Earth Moon distance

From 4π^2 * R^3 = GM*T^2,
got moon revolution period T = sqrt(4π^2 * R^3/(GM))

Earth day in seconds = 23*60*60 + 56*60 + 4
so moon revolution period in Earth day = 27.53

Why it is not 27.32? Is it because the orbit is not circular? But period should be same if R is the semi major axis or the orbit.

If I revise the formula and consider Moon gravitational force to the Earth,
let m be the mass of Moon
T = sqrt(4π^2 * R^3/(G(M+m)))
the moon revolution period in Earth day = 27.36, a bit closer but still some error (rounding error?)
 
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Consider how far the Earth revolves in the lunar month?
 

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