# More complex problem involving momentum

1. Sep 26, 2009

### PolyFX

1. The problem statement, all variables and given/known data
A 0.55 kg block of ice is sliding by you on a very slippery floor at 3.5 m/s. As it goes by, you give it a kick perpendicular to its path. Your foot is in contact with the ice block for 0.0025 seconds. The block eventually slides at an angle of 28 degrees from its original direction (labelled theta in the diagram). The overhead view shown in the diagram is approximately to scale. The arrow represents the average force your toe applies briefly to the block of ice.

What is the unit vector in the direction of the block's momentum after the kick?

What is the x-component of the block's momentum after the kick

What is the magnitude of the block's momentum after the kick?

find the z-component of the block's momentum after the kick

What was the magnitude of the average force you applied to the block?

2. Relevant equations
momentum = (mass)(velocity)
change in momentum = Fnet(time)

3. The attempt at a solution

I honestly have no clue what do do for this particular question. For example, what do I use the given angle (28 degrees) for?

This is how I tried the question:

First multiply the mass of the the block by the speed (0.55 x 3.5)
This will yield the momentum of the block

I don't know where to proceed beyond this point.

I need to find the momentum of the block after the kick. How do I do this? I only know the duration for which the contact occured?

All help will be greatly appreciated.
Thank you.

2. Sep 26, 2009

### kuruman

Say the block initially is moving along the x-direction. You correctly calculated the initial momentum to be 0.55x3.5 kg m/s. That is the initial x-component of the momentum. Now can you find the x-component of the momentum after the kick? Knowing this and the 28o angle, can you find the y-component of the momentum after the kick?

3. Sep 26, 2009

### PolyFX

Hi Kuruman,

I'm having trouble finding the momentum of the block after the kick. I have the initial momentum and I also have the time. Don't I also need Fnet? Or do we assume that Fnet has a x component of 0?

If so then, Final Momentum = Initial Momentum +(Fnet)(t)
So Final Momentum = Initial Momentum?

Actually there was an example in the book with a puck sliding on ice and in that example they also stated that there was no change in momentum. However, I don't know if the same applies to this case.

Thank You

4. Sep 26, 2009

### slider142

Note that momentum is linear and there was no net force in the direction of the block's initial motion, so that component of momentum could not have been affected. It is important that they said the force was applied perpendicularly to the motion, so that is the only momentum component that has changed. Ie., if you label the original non-zero momentum component the x-component, this component may be labelled the y- or the z-component, something perpendicular to the x-component.
Now that you know you have the x-component of the final momentum, you can use the angle and trigonometry to find the missing z-component, as they label it in your question.

5. Sep 26, 2009

### PolyFX

Hi,

Well I got most parts of this question correct but I was not so lucky on others.

So far,

I have found out that the x component of the blocks momentum after the kick is 1.925
I have found out the magnitude of the momentum after the kick is 2.180
I have also found out that the magnitude of the force applied on the block was 409.4 N

However, I cannot get the z component of the unit vector in the direction of the blocks momentum after the kick nor can I get z component of the blocks momentum after the kick.

Here's how I approached the question

Since the x component of the momentum does not change and is constantly at 1.925 I drew a right angled triangle with the x component as the base. I had the angle of the direction of the block which was 28 degrees. Therefore I used the equation

Tan28 = 1.925/Z (where z is the unknown we are trying to find)

Therefore Z = approximately 1.0235

I then used the pythagorean theorem to find out the hypotenuse which was in this case the magnitude of the blocks momentum (2.180).

Thus, I got the momentum of the block after the collision to be (1.925,0,1.0235)
I then divided this vector by 2.180(to get the unit vector) and ended up with (0.883,0,0.4694). both my x and y components are correct but my z component is wrong.

To find the average force applied on the block I divided 1.0235 (z component) by the time interval and got 409.4 N as the answer.

I'm a bit baffled because if the z component that I calculated was incorrect then how did my answer for the average force on the block turn out to be correct (I used the incorrect z value in the calculations)?

Furthermore, if the magnitude and the x component that I calculated were correct. Shouldn't I be able to rearrange the pythagorean theorem to solve for Z^2? This will still yield my initial answer of 1.0235.

I guess there's always the possibility that somehow I just got lucky during the calculation for the average force?

-Thank You

6. Sep 26, 2009

### slider142

I don't see where the question asks for the z-component of the unit momentum vector.