Most powerful test involving Poisson

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safina
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Homework Statement


The number of sales made by a used car salesman, per day, is a Poisson random variable with parameter [tex]\lambda[/tex]. Given a random sample of the number of sales he made on n days, what is the most powerful test of the hypothesis Ho: p = 0.10 versus Ha: p = 0.25, where p is the probability he makes at least one sale (per day)?


Homework Equations


[tex]f\left(x;\lambda\right) = \frac{e^{-\lambda}\lambda^{x}}{x!}[/tex]


The Attempt at a Solution


I applied the single likelihood ratio test which Rejects Ho if [tex]\lambda[/tex] [tex]\leq[/tex] k which I found equivalent in saying to reject Ho if [tex]\sum Xi[/tex] [tex]\leq[/tex] k' where k' is given by [tex]P\left[\sum Xi \leq k'\right] = \alpha[/tex]
But it seems not correct since the hypotheses involve p and not the parameter [tex]\lambda[/tex]. Please help me solve this problem.
 
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what are k & k'?

just a few ideas to get you started:
- first I'd look at how p is related to lambda
- then i would look at the likelihood of each hypothesis
- consider how to derive the power of the test