Consider the series with ascending (but not necessarily sequential) primes p(adsbygoogle = window.adsbygoogle || []).push({}); _{n},

1/p_{1}+1/p_{2}+1/p_{3}+ . . . +1/p_{N}=1, as N approaches infinity.

Determine the p_{n}that most rapidly converge (minimize the terms in) this series. That set of primes I call the "Booda set."

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# Most rapidly convergent reciprocal prime series equal to 1

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