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Motion at Constant Acceleration Question

  1. Jan 14, 2010 #1
    1. The problem statement, all variables and given/known data
    A car accelerates from 13 m/s to 25 m/s in 6.0s. What was its acceleration? How far did it travel in this time? Assume constant acceleration.


    2. Relevant equations
    I used the equation a=v/t


    3. The attempt at a solution
    I got that the acceleration is 2.0 m/s^2. Now my problem in that I am not sure how to go about finding the distance it went in the time.
     
  2. jcsd
  3. Jan 14, 2010 #2
    Does your book give the kinematic equations?
     
  4. Jan 14, 2010 #3
    well it gives me
    v=v0 +at
    x=x0 + v0t+ 1/2 at^2
    v^2 = v^20 + 2a(x -x0)
    v= (v+v0)/2
     
  5. Jan 14, 2010 #4
    v0 is initial velocity, x0 is initial position, and x is final position. How far something travels is the difference between its final and initial positions. Using the second equation should help.
     
  6. Jan 14, 2010 #5
    Okay I got that one thanks so should I post another thread to get help on the next one or should I just ask it here?
     
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