Motion Equation with constant speed (Time sensitive!!) 1. The problem statement, all variables and given/known data A stone thrown horizontally from a height of 6.02m hits the ground at a distance of 12.90m. The initial speed is 11.64 m/s. Calculate the speed of the stone as it hits the ground. Neglect air resistance. 2. Relevant equations v^2-u^2=2as v^2=2as+u^2 3. The attempt at a solution u (initial velocity): 11.64 m/s a (acceleration): 9.81 m/s^2 s (displacement): 12.9-6.02=6.58 m v^2=2*9.81*6.58+11.64^2 v^2=264.59 v=16.27 m/s And that is not right? Any hints or helping suggestions? Thanks!