- #1
Gank
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A block of mass m slides down a ramp. At the bottom, it strikes a block of mass M, which is at rest on a horizontal surface. If the collision is elastic and friction can be ignored, determine the upper limit on mass m if it is to rebound from M, slide up the ramp, stop, slide back down the ramp and collide with M again.
So I have found that:
m(Vi)^2 = m(Vf)^2 + M(W)^2
And that m can only catch M if the velocity Vf is greater than W so the limit becomes Vf=W.
Thanks
So I have found that:
m(Vi)^2 = m(Vf)^2 + M(W)^2
And that m can only catch M if the velocity Vf is greater than W so the limit becomes Vf=W.
Thanks