My physics teacher doesn't teach Physics.

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Discussion Overview

The discussion revolves around the challenges faced by a student in a physics class where the teacher does not provide direct instruction, leading to reliance on self-study and external resources. The focus is on vector calculations, specifically finding magnitudes and directions of vector sums, as well as the application of trigonometric principles in solving these problems.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant expresses frustration with the teacher's approach, stating that they are required to learn from the textbook independently.
  • The participant asks for help with calculating the magnitude of a vector extending from the origin to the point (120 N, -60 N) and expresses confusion about the problem.
  • Another participant suggests obtaining the textbook and provides a link to an external resource for additional help.
  • It is noted that a good understanding of trigonometry, including the Pythagorean theorem and sine and cosine rules, is necessary for solving these types of problems.
  • One participant clarifies that vector B is located in the third quadrant, which is relevant for understanding its direction.
  • The original poster describes their approach to solving the magnitude problem by drawing a right triangle and considering the lengths of the sides.
  • Another participant confirms that the Pythagorean theorem is appropriate for calculating the magnitude of the vector.
  • A suggestion is made to use an online tool (Gizmo) for visualizing vectors and their properties, which could aid in understanding.

Areas of Agreement / Disagreement

Participants generally agree on the need for a textbook and the importance of trigonometry in solving the problems. However, there is no consensus on the best approach to the specific problems presented, and some confusion remains regarding the interpretation of the vector sum direction.

Contextual Notes

Participants express uncertainty about the wording of the problems and the application of trigonometric principles, indicating that assumptions about prior knowledge may not be uniformly held.

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It's true. First day of class he branded himself as a "learning assistor" and he wasn't kididng. He literally doesn't teach and requires us to read the book and learn it on our own. I have a test tomorrow, and I don't have a textbook (problems with ebay) but I do have review sheets so I have a few questions:

Magnitude: What is the formula for calculating it?

Given that a force extends from the origin to (120 N, -60 N) find the magnitude of the vector.

Ok well to be honest, I have no idea how to do this problem :D I think you draw a graph and then draw the vector between 120, -60?

Here's another one:

Vector A has a magnitude of 3.0 units and makes an angle of -90.0 with the positive x-axis, vector B has a magnitude of 4.0 units and makes an angle of -120 with the positive x-axis. What is the direction of the vector sum of A+B referenced to the positive x-axis?

I think the wording confuses me here. I know to draw a graph, and vector A is on the y-axis going downward (negative) and is 3 uints long. Vector B, I'm not sure which way to draw it... does it go in quadrant III or IV? Anyway, because i know its 120 degrees, that means the intersection o fA and B is 30 degrees.. but I'm not sure what hte problem means by what is the direction of the vector sum...

Any help would be much appreciated.
 
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Just to add on, you will need to know your Trigonometry quite well to do these type of question. Namely Pythagorus theorem, sine and cosine rule.
 
BTW vector B is in 3rd quadrant
 
I have a test (today!) and I have no idea when my book will becoming so I really need to learn this. I thought about this problem more and here's what I've come up with:

so I draw a vector from origin (0,0) to (120, -60), an dfrom there I draw a line down to complete the right triangle. So now I have hte opposite and adjacent being 120 and 60 units in length, so from here I can use sin and cosine to solve it? Or pythagorem theorem to solve it?
 
Pythagorean theorem if you're solving for the magnitude of the vector.
 
Create a Free Home User Trial account on

http://www.explorelearning.com/index.cfm?method=Controller.dspTrialPromo"

to gain access to the Gizmo's (otherwise there is a five minute limit on their use, which is too short to learn anything). Go to the Physics Gizmo's in the Science category. Click on the Motion and Force link. You will see a Vectors Gizmo there. Launch it.

Drag the origin of the vectors to the origin of the coordinate systems. You can also change the direction and magnitude of the vectors by dragging their heads (the cursor changes to a hand). These Gizmos are very effective learning tools.
 
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