Natural force of circular motion

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SUMMARY

The discussion focuses on calculating the normal force exerted by a road on a 950kg sports car at the top of a hill with a radius of 86.0m while traveling at 10.0m/s. The normal force equations are derived from the principles of circular motion, specifically using the formula Fn = mg((v²)/(rg) - 1). Additionally, the normal force on the driver, who weighs 73.0kg, is also analyzed, along with determining the car speed at which this normal force equals zero.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with circular motion dynamics
  • Knowledge of force equations in physics
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the concept of centripetal force in circular motion
  • Learn how to derive normal force equations in different scenarios
  • Explore the effects of varying speeds on normal force
  • Investigate real-world applications of circular motion in automotive engineering
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Physics students, automotive engineers, and anyone interested in the dynamics of circular motion and forces acting on vehicles.

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Homework Statement



A 950kg sports car (including driver) crosses the rounded top of a hill (radius = 86.0m) at 10.0m/s.

Homework Equations


A. Determine the normal force exerted by the road on the car.
B. Determine the normal force exerted by the car on the 73.0kg driver.
C. Determine the car speed at which the normal force on the driver equals zero.

The Attempt at a Solution


I started to look at this problem like a loop da loop problem where there are different values of forces depeding on wether your on the top or bottom. Fn top= mg(((v^2)/rg)-1)
 
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