Need Help for solving probability problem

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SUMMARY

The discussion focuses on solving probability problems using the principles outlined in the Schaum's Discrete Mathematics book. Key probabilities provided are P(A) = 0.6, P(B) = 0.3, and P(A and B) = 0.2. The solutions for the problems include calculating P(A but not B), P(B but not A), P(A or B), and P(neither A nor B) using set theory and Venn diagrams. The method involves subtracting the intersection from the individual probabilities to find the required outcomes.

PREREQUISITES
  • Understanding of basic probability concepts
  • Familiarity with set theory and Venn diagrams
  • Knowledge of probability notation (e.g., P(A), P(B), P(A and B))
  • Ability to perform basic arithmetic operations with probabilities
NEXT STEPS
  • Study the principles of conditional probability
  • Learn about the addition and multiplication rules of probability
  • Explore more complex probability problems in Schaum's Discrete Mathematics
  • Practice drawing and interpreting Venn diagrams for probability
USEFUL FOR

Students new to probability, educators teaching probability concepts, and anyone looking to enhance their understanding of discrete mathematics and probability theory.

srinivas2828
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I am new to Probability and i was unable to understand how to find i found this problem in schaum discrete mathematics book.
p(a)=0.6 p(b)=0.3 p(a and b)=0.2 how to find
(a). A but not B occurs
(b).B but not A occurs
(c).A or B occurs
(d).neither A nor B occurs
any help...
 
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Welcome to PF!

Hi srinivas2828! Welcome to PF! :wink:

Let's start with (a).

You have the probabilities of A B and AB,

and you want the probability of AB' (where ' means "not") …

so how can you combine A B and AB to give you AB' ? :smile:

(what must you subtract from A to give AB' ?)
 
Another way to do this: Draw two overlapping circles, representing "A" and "B". The overlap is "A and B". Since P(A)= 0.6 (Please don't write "a" and "A" to mean the same thing!) the "size" of set A is .6. Since P(A and B)= 0.2 the "size" of the overlap is 0.2. What does that leave for the part of A and that is NOT in B (A and not B)?
 

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