Need Help on an Elastic Potential Energy Problem on an incline

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SUMMARY

The discussion focuses on solving an elastic potential energy problem involving a spring with a spring constant of 75 N/m and a mass of 2 kg on a frictionless incline at a 41-degree angle. The key equations used are based on the conservation of mechanical energy, specifically the formula .5mvi^2 + mgyi + .5 kxi^2 = .5 mvf^2 + mgyf + .5 kxf^2. The participants clarify that 'y' represents the vertical height and 'x' represents the extended length of the spring along the slope. The discussion also addresses the impact of kinetic friction on the motion of the mass when attached to the spring.

PREREQUISITES
  • Understanding of conservation of mechanical energy principles
  • Familiarity with spring mechanics and Hooke's Law
  • Basic knowledge of trigonometry and geometry in physics
  • Concept of kinetic friction and its effects on motion
NEXT STEPS
  • Calculate the maximum height reached by the mass on a frictionless incline
  • Explore the effects of different spring constants on motion
  • Investigate the role of kinetic friction in energy loss during motion
  • Learn about energy conservation in systems with multiple forces acting
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to explain concepts related to energy conservation and spring dynamics.

portuwhat
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Homework Statement


A spring (k=75 N/m) has an equilibrium length of 1 m. The spring is compressed to a length of .5 m and a mass of 2 kg is placed at its free end on a frictionless slope which makes an angle of 41 degrees with respect to the horizontal. The spring is then released. a) If the mass is not attached to the spring, how far up the slope will the mass move before coming to rest? b) If the mass is attached to the spring, how far up the slope will the mass move before coming to rest? c) Now the incline has a coefficient of kinetic friction. If the block, attached to the spring, is observed to stop just as it reaches the spring's equilibrium position, what is the coefficient of friction?


Homework Equations


Conservation of mechanical energy
.5mvi^2 + mgyi + .5 kxi^2 = .5 mvf^2 + mgyf + .5 kxf^2


The Attempt at a Solution


So I began using the conservation of mechanical energy but I'm not even sure where to begin with that. What do I say the y is or x is in the equation? I have no clue, is there anyway someone can explain this to me without giving me the answer? Thanks.
 
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Welcome to PF!

portuwhat said:
Conservation of mechanical energy
.5mvi^2 + mgyi + .5 kxi^2 = .5 mvf^2 + mgyf + .5 kxf^2

What do I say the y is or x is in the equation?

Hi portuwhat! Welcome to PF! :smile:

This is just geometry …

y is the height (measured vertically, of course).

x is the extended length of the spring (measured along the 41º slope).

Have a go! :wink:
 

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