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Homework Help: Need help on projectile motion by 10:00 tonight (~ 2 hrs 10 mins from now)

  1. Nov 13, 2007 #1
    1. The problem statement, all variables and given/known data

    A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. The plane is traveling horizontally with a speed of 280 km/h (77.8 m/s).

    a) How far in advance of the recipients (horizontal distance) must the goods be dropped (Fig. 3 41a)? Already figured this out and got it right: 538.8 m

    b) Suppose, instead, that the plane releases the supplies a horizontal distance of 425 m in advance of the mountain climbers. What vertical velocity (up or down) should the supplies be given so that they arrive precisely at the climbers' position (Fig. 3 41b)?
    Magnitude: ???

    2. Relevant equations

    3. The attempt at a solution
    Part A work:

    x= 538.8 m
    Part B work

    t=1.5 s

    tfinal= 6.93s - 1.5s
    tfinal = 5.5s

    vy0~= 70 m/s

    I think I did this problem right, but the computer keeps saying that it's wrong. Is this a rounding error? I have tried 70 m/s, but it said that was wrong so I think that I might have to round to 69.7 m/s instead of 70 m/s since the computer is picky sometimes. I only have one chance left to get it right. :P

    If this isn't a rounding error, what have I done wrong? Any help is appreciated, thanks.
  2. jcsd
  3. Nov 13, 2007 #2
    your values for y and y0 need to be switched. because 0 is not your initial height, 235 is. also, if you designated up as positive and down as negative, your generic equation should be y=y0-(vy0)t-0.5gt^2. try that.
  4. Nov 13, 2007 #3
    Wow, that was obvious. Thank you, it worked. :)
  5. Nov 13, 2007 #4
    you're welcome =) glad I could help.
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