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RandomStudentNotused
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- Homework Statement
- Hello. Recently in my class we started Projectile motion but I seem to have some trouble. Can you help me with these questions?
- Relevant Equations
- v=u+at
vSinθ
vCosθ
S=ut
v=ut+1/2at²
V²=U² + 2as
1)Find the range of the gun when the muzzle speed is 400m/s and the elevation 24.5°
- I tried to find " Time " via t= [v-u]/a by substituting it through cos-->
t= ( 0- [400cos24.5] )/-10 and got [ 36.39 ].
Which I then substituted in S=ut---> S= ( 400cos24.5 ) x 36.39=13245.3.
[ the answer in the answer key is 10.9 km ]
2)A target is 10 km from a gun and the gun's muzzle speed is 400 m/s. What angle of projection. What angle of projection will ensure a hit?
-- I used cos-1 (10000/400 ) and got cos-1(25). I think its wrong.
So I tried θ = 400sin24.5=165.877
[ the answer in the answer key is 71° 5' ; 18° 55' ]
3)A projectile has a muzzle speed of 70 m/s. what is the range on a horizontal plane if the angle of projection is 15° . Find the error, at this range if the error in the elevation is 0.25°
- I used t = v - u/ a and substituted the values in T= ( 0 - 70sin15 ) / -10=1.81
And using formula S=ut, I multiplied it--->S= ( 70cos15 ) x 1.81=122.5 m[ the answer in the answer key is 250m ; ± .7.6 m ]
-----
PS: Can you tell me, when do you use cos and sin in questions like these?
-do you use sin when something goes up or is in the air? And cos for horizontal range of a projectile/object?
If you can help,it would be much appreciated
- I tried to find " Time " via t= [v-u]/a by substituting it through cos-->
t= ( 0- [400cos24.5] )/-10 and got [ 36.39 ].
Which I then substituted in S=ut---> S= ( 400cos24.5 ) x 36.39=13245.3.
[ the answer in the answer key is 10.9 km ]
2)A target is 10 km from a gun and the gun's muzzle speed is 400 m/s. What angle of projection. What angle of projection will ensure a hit?
-- I used cos-1 (10000/400 ) and got cos-1(25). I think its wrong.
So I tried θ = 400sin24.5=165.877
[ the answer in the answer key is 71° 5' ; 18° 55' ]
3)A projectile has a muzzle speed of 70 m/s. what is the range on a horizontal plane if the angle of projection is 15° . Find the error, at this range if the error in the elevation is 0.25°
- I used t = v - u/ a and substituted the values in T= ( 0 - 70sin15 ) / -10=1.81
And using formula S=ut, I multiplied it--->S= ( 70cos15 ) x 1.81=122.5 m[ the answer in the answer key is 250m ; ± .7.6 m ]
-----
PS: Can you tell me, when do you use cos and sin in questions like these?
-do you use sin when something goes up or is in the air? And cos for horizontal range of a projectile/object?
If you can help,it would be much appreciated
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