Projectile Motion -- Help please understanding these basic problems

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Homework Help Overview

The discussion revolves around projectile motion problems, specifically calculating the range of a projectile based on muzzle speed and angle of elevation, as well as determining the angle of projection needed to hit a target at a specified distance. Participants are exploring the relationships between the components of motion and the use of trigonometric functions in these calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss various attempts to calculate time of flight and range using trigonometric functions, questioning the use of sine and cosine in different contexts. There is also a focus on understanding the underlying principles of projectile motion.

Discussion Status

Some participants are providing guidance on the correct application of trigonometric functions and suggesting the need for sketches to visualize the problem. There is an acknowledgment of confusion regarding the use of sine and cosine, with some humor about common mistakes. The discussion appears to be ongoing with multiple interpretations being explored.

Contextual Notes

Participants are working under the constraints of homework problems, which may limit the information available for discussion. There are references to answer keys that differ from participants' calculations, indicating potential misunderstandings or misapplications of concepts.

RandomStudentNotused
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Homework Statement
Hello. Recently in my class we started Projectile motion but I seem to have some trouble. Can you help me with these questions?
Relevant Equations
v=u+at
vSinθ
vCosθ
S=ut
v=ut+1/2at²
V²=U² + 2as
1)Find the range of the gun when the muzzle speed is 400m/s and the elevation 24.5°

- I tried to find " Time " via t= [v-u]/a by substituting it through cos-->

t= ( 0- [400cos24.5] )/-10 and got [ 36.39 ].

Which I then substituted in S=ut---> S= ( 400cos24.5 ) x 36.39=13245.3.

[ the answer in the answer key is 10.9 km ]

2)A target is 10 km from a gun and the gun's muzzle speed is 400 m/s. What angle of projection. What angle of projection will ensure a hit?

-- I used cos-1 (10000/400 ) and got cos-1(25). I think its wrong.

So I tried θ = 400sin24.5=165.877

[ the answer in the answer key is 71° 5' ; 18° 55' ]

3)A projectile has a muzzle speed of 70 m/s. what is the range on a horizontal plane if the angle of projection is 15° . Find the error, at this range if the error in the elevation is 0.25°

- I used t = v - u/ a and substituted the values in T= ( 0 - 70sin15 ) / -10=1.81

And using formula S=ut, I multiplied it--->S= ( 70cos15 ) x 1.81=122.5 m[ the answer in the answer key is 250m ; ± .7.6 m ]

-----

PS: Can you tell me, when do you use cos and sin in questions like these?

-do you use sin when something goes up or is in the air? And cos for horizontal range of a projectile/object?
If you can help,it would be much appreciated
 
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Hello student, @RandomStudentNotused (?)
:welcome: !​

RandomStudentNotused said:
1)Find the range of the gun when the muzzle speed is 400m/s and the elevation 24.5°

- I tried to find " Time " via t= [v-u]/a by substituting it through cos-->

t= ( 0- [400cos24.5] )/-10 and got [ 36.39 ].

So it looks as if you think the horizontal velocity (*) at the end (your symbol ##\ v\ ##) will be zero. If you make a sketch, that can be seen to be very unlikely :rolleyes:

(*) or did you mean vertical :wink: ? Check ##\sin## and ##\cos## definitions !

Free tips:
  • Make a sketch
  • Fill in the known / given data as symbols
  • Mark the variable / quantity you are looking for
  • Search for appropriate variables on the path from given to searched for, and write down the relationships in terms of symbols
  • Check dimensions
  • Do the math
  • Check the answer
  • Check the answer
You're doing several of them already, so you're on the right path!
 
RandomStudentNotused said:
PS: Can you tell me, when do you use cos and sin in questions like these?
My only advice on this is that you use the cosine when it's the cosine, and you use the sine when it's the sine! And if you get them mixed up now and again, then you're in good company.
 
Your working suggests you don't really understand what you are doing (sorry)!

At the risk of being accused of self-promotion, try this video:


(Edit -typo's corrected.)
 
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Likes   Reactions: Lnewqban and BvU
Steve4Physics said:
At the risk of being accused of self promotion
Haha, on the contrary ! A real treasure trove of didactics ! Well done !
 

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