(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

At the instant the traffic light turns green, a car that has been waiting at an intersection starts ahead with a constant acceleration of 3.60 m/s^2. At the same instant a truck, traveling with a constant speed of 20.5 m/s, overtakes and passes the car.

How far beyond its starting point does the car overtake the truck?

How fast is the car traveling when it overtakes the truck?

2. Relevant equations

(V_{x})^{2}=(V_{0x})^{2}+2a_{x}(x-x_{0})

3. The attempt at a solution

First, I realized that time wasn't involved in the equation. That's how I knew how what equation to use. Then i tried converting it into a_{x}= ((V_{x})_{2}-(V_{0x})_{2})/2(X-X_{0}). After plugging in all the numbers: 3.60 m/s^2 being the acceleration and 20.5 i believe is just the absolute value of the velocity so i plugged that in as the second velocity. Through out the problem i was trying to figure out x... which turned out to be x= 420.25/7.20 m= 58.36. But then the question asks how far beyond it's starting point does the car overtake the truck??? how do i figure that out after figuring out x, which is the distance at which the truck overpassed the car.... can someone help me?

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# Homework Help: Need Help with problems involving constant acceleration and constant speed. :/

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