Need to make sure I am doing these problems correctly.

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SUMMARY

The discussion focuses on solving measurement problems related to mass and weight, specifically converting the mass of liquids into pounds and ounces. The calculations involve determining the weight of a pint of English Bitter and pure clear water based on their respective masses of 3.831 Kg and 3.785 Kg per gallon. The user correctly applies the conversion factors, concluding that one pint of English Bitter weighs approximately 1.056 lbs, while one pint of water weighs approximately 0.473 lbs. The final task is to find the difference in mass between the two pints in ounces, which is achieved by converting the weight difference into ounces.

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  • Familiarity with unit conversion factors (Kg to lbs, gallons to pints)
  • Basic arithmetic operations (division, subtraction)
  • Knowledge of measurement units (pints, pounds, ounces)
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Students tackling measurement problems, educators teaching unit conversions, and anyone involved in brewing or cooking that requires precise measurements of liquids.

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Measurement problems: Mass, weight, unit conversion

Homework Statement


There are 8 pints to a gallon. One gallon of good English Bitter, ready to drink, has a mass of 3.831 Kg. One gallon of pure clear water, also at drinking temperature, has a mass of 3.785 Kg. A pound, on the other hand, is anything that has a mass of 0.4535 Kg. There are, by definition, 16 ounces in a pound

a. How heavy is a pint of English Bitter in pounds
b. How heavy is a pint of pure clear water in pounds
c. How much more massive is a pint of Bitter than a pint of water in ounces?


Homework Equations


1 galbitter = 3.831 Kg
1 galpure = 3.785
1 gal = 8 pints
1 lb = 0.4535 Kg
1 lb = 16 ounces



The Attempt at a Solution



So, for a I took 1 galbitter= (3.831Kg/1gal) x (1lb/0.4535Kg) = 8.44762955 lbs per gallon of bitter. I then took 8.447562955 lbs per gallon of bitter/8pints
8.447562955/8 to get the weight of 1 pint of bitter? Is this the correct way to do point a? If it is then I can do point b, no problem. And for point c, I can just subtract and find the difference after multiplying the weights of each pint of liquid by 16 oz, right?
 
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Jdpaul88 said:

Homework Statement



Homework Equations


1 galbitter = 3.831 Kg
1 galpure = 3.785
1 gal = 8 pints
1 lb = 0.4535 Kg
1 lb = 16 ounces

The Attempt at a Solution



So, for a I took 1 galbitter= (3.831Kg/1gal) x (1lb/0.4535Kg) = 8.44762955 lbs per gallon of bitter. I then took 8.447562955 lbs per gallon of bitter/8pints
8.447562955/8 to get the weight of 1 pint of bitter? Is this the correct way to do point a? If it is then I can do point b, no problem. And for point c, I can just subtract and find the difference after multiplying the weights of each pint of liquid by 16 oz, right?

Your method looks ok. I didn't run your numbers. Good luck and Welcome to PF.
 


LowlyPion said:
Your method looks ok. I didn't run your numbers. Good luck and Welcome to PF.

Thanks for the input. Good to meet you.
 


Jdpaul88 said:
Thanks for the input. Good to meet you.

Cheers then.

Enjoy your bitters and beer.
 
So you think that this setup is fine?
 

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