Negative or Positive Partial Derivative

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SUMMARY

The discussion focuses on calculating the partial derivatives of the variable n with respect to pressure (P) and temperature (T) using the equations: \frac {\partial n}{\partial P} = \frac{nb -1}{\left(2an-Pb-3abn^2-kT\right )} and \frac {\partial n}{\partial T}= \frac {nk}{\left(2an-Pb-3abn^2-kT \right )}. The participant confirms that a positive partial derivative indicates an increase in n with respect to the independent variable, while a negative one indicates a decrease. They express uncertainty about determining the sign of the derivatives and suggest expressing them in terms of positive combinations like (P+an^2) and nkT.

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Saptarshi Sarkar
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Homework Statement
A non-ideal gas is described by the VdW law

##(P+an^2)(1-nb) = nkT##

where a,b and k are positive constants, n is the density of particles, P the pressure, and T the temperature.
How will n change (increase or decrease) if we

1) Hold P and increase T
2) Hold T and increase P
Relevant Equations
##(P+an^2)(1-nb) = nkT##
My attempt

I calculated the partial derivatives of n wrt P and T. They are given below.

##\frac {\partial n}{\partial P} = \frac{nb -1}{\left(2an-Pb-3abn^2-kT\right )}##
##\frac {\partial n}{\partial T}= \frac {nk}{\left(2an-Pb-3abn^2-kT \right ) }##

I know that if the partial derivative is positive, n should increase with the increase in the independent variable and if the partial derivative is negative, n should decrease with the increase in the independent variable. But, I am not sure how to determine if the above partial derivatives are positive or negative.
 
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Both ##(P+an^2)## and ##nkT## are positive, so you know that ##(1-nb)## is positive. Try expressing your partial derivatives in terms of those combinations.
 
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vela said:
Both ##(P+an^2)## and ##nkT## are positive, so you know that ##(1-nb)## is positive. Try expressing your partial derivatives in terms of those combinations.

Thanks a lot!
 

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