Net Forces and Tension Practice Problems

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This discussion focuses on solving tension problems in physics, specifically using free body diagrams (FBD) for blocks of varying masses. The user is practicing problems from the website Education.com and is encountering difficulties with problem 6. Key equations derived include F = T - Mg for a mass M, and F = 2Mg + T' - T = 2Ma for a mass 2M. The user concludes that the correct acceleration for the system is 8.6 m/s², despite initial calculations suggesting otherwise.

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bulbasaur88
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I'm trying to improve on tension problems so I am practicing using this website: http://www.education.com/study-help/article/tension/

I am on problem 6, but I keep coming up with the wrong answers. I attempted this by trying to show the net forces for each box.

Box M net forces
T upwards
Mg downwards
F = T - Mg = Ma

Box 2M net forces
T upwards
T' downwards
***should I include the weight (2Mg) of this box?

Box 4M net forces
4Mg downwards
T' upwards
F = 4Mg - T' = 4Ma

I have a feeling there is an error in box 2M that is fudging with my results. Lastly, does T = 6Mg? Help?? :confused:
 
Last edited:
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bulbasaur88 said:
I'm trying to improve on tension problems so I am practicing using this website: http://www.education.com/study-help/article/tension/

I am on problem 6, but I keep coming up with the wrong answers. I attempted this by trying to show the net forces for each box.

Box M net forces
T upwards
Mg downwards
F = T - Mg = Ma
yes
Box 2M net forces
T upwards
T' downwards
***should I include the weight (2Mg) of this box?
always include the weight in any free body diagram
Box 4M net forces
4Mg downwards
T' upwards
F = 4Mg - T' = 4Ma
yes
I have a feeling there is an error in box 2M that is fudging with my results. Lastly, does T = 6Mg? Help?? :confused:
yes, correct your error for the net forces acting in the FBD of the 2M block.
 
was my error that I didn't include the weight? or is it another entirely separate error in block 2m?
 
Is the equation for block 2m:

F = 2Mg + T' - T = 2Ma?
 
bulbasaur88 said:
Is the equation for block 2m:

F = 2Mg + T' - T = 2Ma?
yes. Now solve for T, T', and a. (Note: T is not equal to 6Mg)
 
I solved it and it still incorrect.

Block M
T - mg = ma <---plug in m = 1 Kg
T - 9.8 = a
T = 9.8 + a equation 1

Block 2M
T' + 2mg - T = 2ma <---Plug in m = 1 kg
T' + 2(9.8) - T = 2a
T' + 19.6 - T = 2a equation 2

Block 4M
4mg - T' = 4ma < --- plug in m = 1 kg
4(9.8) - T' = 4a
T' = 39.2 - 4a equation 3

Substitute equation 1 and equation 3 into equation 2
equation 2: T' + 19.6 - T = 2a
(39.2 - 4a) + 19.6 - (9.8 + a) = 2a
Solve for a.

a = 7 m/s^2

Correction answer is 8.6 m/s^2.
 
We were correct :D

The answer provided is incorrect I believe. Someone solved it out and got the same answer as I did here, http://www.myteacherpages.com/webpages/niedzielam/files/AP%20Review%2001%20Tension%20SOLUTIONS.pdf .
 
Last edited by a moderator:
Thank you phanthomjay *air hug*
 

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