Net Work Done: Solve Force Question Homework

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Homework Help Overview

The problem involves calculating the net work done on an object by considering the forces acting on it, specifically a given force and a friction force, along with their respective displacements. The subject area pertains to mechanics, particularly the concepts of work and forces.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of work using the equation W=F·D, with attempts to incorporate both the applied force and friction force into their calculations. Questions arise regarding the treatment of the friction force and its impact on the overall work done.

Discussion Status

Participants are actively engaging with the problem, sharing their calculations and questioning the correctness of their approaches. Some guidance has been provided regarding the use of the friction force in the work equation, and there is a recognition of discrepancies in the expected results.

Contextual Notes

There is a mention of the mass being negligible, which affects the calculation of the friction force, but the friction force value is already provided. Participants are exploring the implications of this condition on their calculations.

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Homework Statement


A force F=-4.3i+2.0j+1.5k Newtons exerts a displacement of d=-0.8i+1.8j+-3.6k metres upon a small (ie mass is negligible) object. If the friction force is equal to Ffr=-0.2,, then what is the net work done upon the object?


Homework Equations





The Attempt at a Solution


I know the net work is the sum of all the individual work and the work equation is W=F.D. So i tried to work out the work of the initial force stated by multiplying the force and displacement stated which i got 1.64J. I think the only other work is caused by the friction force but when i try to work that out (because the mass is negligable) i get 0. Can someone please help?
 
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Mass is negligible only affects calculating the friction force using [itex]\mu N[/itex], but you already have the friction force. What can you do with it?
 
could i put it as the force in the work equation and put the distance as the displacement that's stated in the question?
 
Yes.
 
so i have 1.64 from the first force i worked out and if i put the friction force into the work equation w= -0.2 x D i get -0.82. If I add the two works i have i get 0.82, but the answer is 1.3... can you give me hints on what I've done wrong??
 
I get that also. From where did you get this problem?
 

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