POTW Neumann Boundary Value Problem in a Half Plane

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The discussion focuses on solving the Neumann boundary value problem for the Laplace equation in a half-plane, specifically finding bounded solutions to the PDE Δu(x,y) = 0 for x in R and y > 0. The boundary condition given is u_y(x,0) = g(x), where g(x) is a specified function. Participants explore various methods for finding solutions, including Fourier transforms and separation of variables. The implications of the boundary condition on the existence and uniqueness of solutions are also examined. Overall, the conversation emphasizes the mathematical techniques applicable to this type of boundary value problem.
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Find all bounded solutions to the PDE ##\Delta u(x,y) = 0## for ##x\in \mathbb{R}## and ##y > 0## with Neumann boundary condition ##u_y(x,0) = g(x)##.
 
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Let ##\hat{u}(k,y) = \int_{-\infty}^\infty u(x,y)e^{ikx}\, dx##, the Fourier transform of ##u## with respect to the first variable. Applying this Fourier transform to the PDE with respect to the first variable yields ##\hat{u}_{yy} - k^2 \hat{u} = 0## with ##\hat{u}_y(k,0) = \hat{g}(0)##. We have general solution ##\hat{u}(k,y) = A(k)e^{ky} + B(k) e^{-ky}##. Assuming boundedness of ##u##, ##A(k) \equiv 0## if ##k > 0## and ##B(k) \equiv 0## if ##k < 0##. So we express ##\hat{u}(k,y) = C(k)e^{-|k|y}##. The condition ##\hat{u}_y(k,0) = \hat{g}(k)## forces ##-|k| C(k) = \hat{g}(k)##. Therefore ##\hat{u}_y(k,y) = -|k| C(k) e^{-|k|y} = \hat{g}(k) e^{-|k|y}##. By the convolution theorem we obtain $$u_y(x,y) = \frac{y}{\pi} \int_{-\infty}^\infty \frac{g(x-t)}{t^2 + y^2}\, dt$$ Integrating with respect to ##y## produces solution ##u(x,y) = \frac{1}{2\pi} \int_{-\infty}^\infty g(x-t) \log(t^2 + y^2)\, dt + c##.
 
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