Neutralisation Cont'd: Heat of Neutralization & Final Temperature

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SUMMARY

The discussion centers on the calculation of the heat of neutralization and the final temperature after a reaction involving sulfuric acid (H2SO4) and sodium hydroxide (NaOH). The calculated final temperature of 121.75 °C is deemed unreasonable due to incorrect mass selection in the energy balance equation. The heat of neutralization is confirmed at -55.9 kJ/mol, and the correct approach requires using the total mass of the reactants rather than just the mass of water produced. This ensures accurate calculations in thermodynamic assessments.

PREREQUISITES
  • Understanding of heat of neutralization in acid-base reactions
  • Familiarity with thermodynamic equations, specifically energy balance
  • Knowledge of molarity and molar mass calculations
  • Basic principles of pH and its relation to hydrogen ion concentration
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  • Review thermodynamic principles related to heat transfer in reactions
  • Study the calculation of final temperature in exothermic reactions
  • Learn about the role of total mass in energy balance equations
  • Explore practical applications of heat of neutralization in industrial processes
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Chemistry students, chemical engineers, and anyone involved in thermodynamic calculations related to acid-base reactions.

pikkie
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I solved for the heat of neutralization already, I thought, but now, I got the final temperature after reaction is 121.75 oC which I think is too big.

I start with initial pH = 2 and final the conc H+ = 10^-(pH=2) then I find the mole by multipling the conc with the tank volume (400m3), the I find the mass by multiply it with MW.

To neutralise 1 mole of H+, I need 1 mole of OH-, so I balance the mole of OH- needed with the mole of H+ I calculated justnow. The I got the mass and volume of NaOH needed to neutralize the pH 2.

The heat of neutralization is -55.9 kJ/mol. The energy balance is (m.Cp.del_T)in = (m.del_H) + (m.Cp.del_T)out

But since i use the initial temperature and reference temperature both also 25 oC, so the (m.Cp.del_T)in is cancelled. What left is only
-(m.del_H) = (m.Cp.del_T)out

The part that confused me here is what m should I use for these m.del_H and m.Cp.del_T. I obtained the answer stated ealier (121.75 oC) by using the mass for m.del_H is the mass of water produced and the mass for m.Cp.del_H is the mass of the total mass of NaOH+H2SO4 that reacted. Is this correct? If yes, is the temperature I got reasonable? If not, what's my mistake?
 
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pikkie said:
The part that confused me here is what m should I use for these m.del_H and m.Cp.del_T. I obtained the answer stated ealier (121.75 oC) by using the mass for m.del_H is the mass of water produced and the mass for m.Cp.del_H is the mass of the total mass of NaOH+H2SO4 that reacted. Is this correct? If yes, is the temperature I got reasonable? If not, what's my mistake?
"Correct?" No. "Reasonable temperature?" No. Use the total mass, not "selected" sub-totals.
 

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